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Ira Lisetskai [31]
3 years ago
5

Substance X has a fixed volume, and the attraction between its particles is strong. Substance Y has widely spread out particles

and can be compressed. What can most likely be concluded about these substances?
Chemistry
1 answer:
DedPeter [7]3 years ago
4 0

Answer: X is a Solid; Y is a Gas

Explanation:

There are three (3) states of matter. They are: Solid, Liquid and Gases.

Substance X and Y, belong to the states of matter.

A Solid is a substance that retains its SIZE and SHAPE without need of a container (as opposed to a liquid or gas).

Thus, it will most likely be concluded that: substance X is a Solid; while Y is a Gas

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Some radioactive nuclides have very short half-lives, for example, I-31 has a half-life of approximately 8 days. Pu-234, by comp
lorasvet [3.4K]

Answer:

Here's what I find.

Explanation:

Iodine-131

Iodine-131 is both a beta emitter and a gamma emitter.

_{53}^{131}\text{I}\longrightarrow \, _{54}^{131}\text{Xe} +\, _{-1}^{0}\text{e} +\, _{0}^{0}\gamma

About 90 % of the energy is β-radiation and 10 % is γ-radiation. Both forms are highly energetic.

The main danger is from ingestion. The iodine concentrates in thyroid gland, where the β-radiation destroys cells up to 2 mm from the tissues that absorbed it.

Both the β- and γ-radiation cause cell mutations that can later become cancerous. Small doses, such as those absorbed from the nuclear disasters in the Ukraine and Japan, can cause cancers years after the original iodine has disappeared.

Plutonium-239

Plutonium-239 is an alpha emitter.

_{94}^{239}\text{U} \longrightarrow \, _{92}^{235}\text{Xe} + \, _{2}^{4}\text{He}

Alpha particles cannot penetrate the skin, so external exposure isn't much of a health risk.

However, they are extremely dangerous when they are inhaled and get inside cells. They travel first to the blood or lymph system and later to the bone marrow and liver, where they cause up to 1000 times more chromosomal damage than beta or gamma rays.

It takes about 20 years for plutonium to be eliminated from the liver around 50 years for from the skeleton, so it has a long time to cause damage.

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Wind power is:
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Answer) All of the above
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Oksana_A [137]

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2 years ago
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1. A solution with a pH of 9 has a pOH of
Alecsey [184]

Answer:

strength = 10⁻²/10⁻³ = 10 times more acidic

Explanation:

1. A solution with a pH of 9 has a pOH of

pH + pOH = 14 => pOH = 14 - pH = 14 - 9 = 5

2. Which is more acidic, a solution with a pH of 6 or a pH of 4?

pH of 4 => Higher [H⁺] = 10⁻⁴M vs pH of 6 => [H⁺] = 10⁻⁶M

3. How many times more acidic is a solution with a pH of 2 than a solution with a pH of 3?

soln with pH = 2 => [H⁺] = 10⁻²M

soln with pH = 3 => [H⁺] = 10⁻³M

strength = 10⁻²/10⁻³ = 10 times more acidic

4. What is the hydrogen ion concentration [H + ] in a solution that has a pH of 8?

[H⁺] = 10^-pH = 10⁻⁸M

5. A solution has a pOH of 9.6. What is the pH? (Use the formula.)

pH + pOH = 14 => pH = 14 - 9.6 = 4.4

8 0
3 years ago
20.00 g of aluminum (Al) reacts with 78.78 grams of molecular chlorine (Cl2), all of each reaction is completely consumed and as
shepuryov [24]

The reaction forms 98.76 g AlCl_3.  

We have the masses of two reactants, so this is a <em>limiting reactant problem</em>.

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.  

<em>Step 1. Gather all the information</em> in one place with molar masses above the formulas and everything else below them.  

M_r: ___26.98 _70.91 __133.34

________2Al + 3Cl_2 → 2AlCl_3

Mass/g: 20.00 _78.78

<em>Step 2</em>. Calculate the <em>moles of each reactant</em>  

Moles of Al = 20.00 g Al × (1 mol Al /26.98 g Al) = 0.741 29 mol Al

Moles of Cl_2 = 78.78 g Cl_2 × (1 mol Cl_2 /70.91 g Cl_2) = 1.11 10 mol Cl_2

Step 3. Identify the <em>limiting reactant</em>  

Calculate the moles of AlCl_3 we can obtain from each reactant.  

<em>From Al</em>: Moles of AlCl_3 = 0.741 29 mol Al × (2 mol AlCl_3/2 mol Al) = 0.741 29 mol AlCl_3

<em>From Cl_2</em>: Moles of AlCl_3 = 1.11 10 mol Cl_2 × (2 mol AlCl_3/3 mol Cl_2) = 0.740 66 mol AlCl_3

<em>Cl_2 is the limiting reactant</em> because it gives the smaller amount of AlCl_3.

<em>Step 4</em>. Calculate the <em>mass of AlCl_3</em>.

Mass = 0.740 66 mol AlCl_3 × 133.34 g/1 mol AlCl_3 = 98.76 g AlCl_3

The reaction produces 98.76 g AlCl_3.

4 0
3 years ago
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