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hammer [34]
3 years ago
12

for the function Y=3(3/4)^x , identify the Y-intercept and determine whether it is increasing or decreasing

Mathematics
1 answer:
lilavasa [31]3 years ago
4 0

The derivative of a function may be used to determine whether the function is increasing or decreasing on any intervals in its domain. If f′(x) > 0 at each point in an interval I, then the function is said to be increasing on I. f′(x) < 0 at each point in an interval I, then the function is said to be decreasing on I.Intervals of increasing, decreasing or constant ALWAYS pertain to x-values. Do NOT read numbers off the y-axis. Stay on the x-axis for these intervals! Intervals of Increasing/Decreasing/Constant: Interval notation is a popular notation for stating which sections of a graph are increasing, decreasing or constant.A function f(x) increases on an interval I if f(b) ≥ f(a) for all b > a, where a,b in I. If f(b) > f(a) for all b>a, the function is said to be strictly increasing.The slope and y-intercept values indicate characteristics of the relationship between the two variables x and y. The slope indicates the rate of change in y per unit change in x. The y-intercept indicates the y-value when the x-value is 0.

I hope this helps

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If possible step by step explanation. thank you!
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Answer:

A

Step-by-step explanation:

\frac{(3x^{2} )^\frac{1}{2} }{3^\frac{1}{2} } =3

(3x^2)^\frac{1}{2} = 3^\frac{1}{2} x

Remember that \frac{x^b}{x^c} =x^(b-c)

Using that \frac{3^\frac{1}{2}x }{3^\frac{1}{2} }=3^(1/2x-1/2)=3^((x-1)/2)

3^\frac{x-1}{2} =3^1

So we can say: \frac{x-1}{2} =1, because the bases are the same

We can multiply both sides of the equation by 2. We get x-1=2, and x=3. Which is A.

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Step-by-step explanation:

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