Answer: The heat absorbed by the water is 52.823 J.
Explanation:
Given: Mass of metal = 5.05 g
Specific heat of water = 4.184 ![J/g^{o}C](https://tex.z-dn.net/?f=J%2Fg%5E%7Bo%7DC)
Initial temperature = ![24.8^{o}C](https://tex.z-dn.net/?f=24.8%5E%7Bo%7DC)
Final temperature = ![27.3^{o}C](https://tex.z-dn.net/?f=27.3%5E%7Bo%7DC)
Formula used to calculate heat absorbed is as follows.
![q = m \times C \times (T_{2} - T_{1})](https://tex.z-dn.net/?f=q%20%3D%20m%20%5Ctimes%20C%20%5Ctimes%20%28T_%7B2%7D%20-%20T_%7B1%7D%29)
where,
q = heat
m = mass of substance
= initial temperature
= final temperature
Substitute the values into above formula as follows.
![q = m \times C \times (T_{2} - T_{1})\\= 5.05 g \times 4.184 J/g^{o}C \times (27.3 - 24.8)^{o}C\\= 52.823 J](https://tex.z-dn.net/?f=q%20%3D%20m%20%5Ctimes%20C%20%5Ctimes%20%28T_%7B2%7D%20-%20T_%7B1%7D%29%5C%5C%3D%205.05%20g%20%5Ctimes%204.184%20J%2Fg%5E%7Bo%7DC%20%5Ctimes%20%2827.3%20-%2024.8%29%5E%7Bo%7DC%5C%5C%3D%2052.823%20J)
Thus, we can conclude that heat absorbed by the water is 52.823 J.
When exercising, we respire. When we do not do exercise that often, our muscles will not be able to withstand long amounts of exercise due to lack of oxygen. This is called Anaroebic Respiration. This is when glucose turns to Lactic Acid immediately. Anaerobic respiration releases less energy.
Answer:
5.112 grams of simple sugar glucose is produced by the reaction of 7.50 g of carbon dioxide.
Explanation:
![6CO_2+6H_2O\rightarrow C_6H_{12}O_6+6O_2](https://tex.z-dn.net/?f=6CO_2%2B6H_2O%5Crightarrow%20C_6H_%7B12%7DO_6%2B6O_2)
Moles of carbon dioxide = ![\frac{7.50 g}{44 g/mol}=0.1704 mol](https://tex.z-dn.net/?f=%5Cfrac%7B7.50%20g%7D%7B44%20g%2Fmol%7D%3D0.1704%20mol)
According to reaction 6 moles of carbon dioxide gives 1 mole of glucose.
Then 0.1704 moles of carbon dioxide will give:
of glucose
Mass of 0.0284 moles of glucose:
0.0284 mol 180 g/mol =5.112 g[/tex]
5.112 grams of simple sugar glucose is produced by the reaction of 7.50 g of carbon dioxide.
Answer:
Given Elements are
- Ferrus(Fe)
- Zinc(Zinc)
- Sodium (Na)
- Copper (Cu)
- Silver(Ag)
<h3>Decreasing Order:-</h3>
Na>Zn>Fe>Cu>Ag
<h3><u>Expla</u><u>nation</u><u>:</u><u>-</u></h3>
- Here is the reactivity series of elements to let you understand better .
![\setlength{\unitlength}{0.8 cm}\begin{picture}(20,15)\thicklines\put(5,9.5){\large {\boxed{ \sf{Reactivity \: series}}}}\put(0.8,8){\large\sf K \qquad\qquad\qquad Potassium\qquad\qquad\qquad \: maximum}\put(0.8,7.2){\large\sf Na \qquad\qquad\qquad Sodium\qquad\qquad\qquad\quad \: reactivity}\put(0.8,6.2){\large\sf Ca\qquad\qquad\qquad \: Calcium}\put(0.8,5.2){\large\sf Mg\qquad\qquad\quad \: Magnesium}\put(0.8,4.2){\large\sf Al\qquad\qquad\qquad \: Aluminium\qquad\qquad\qquad \: decreasing}\put(0.8,3.2){\large\sf Zn\qquad\qquad\quad\qquad \: Zinc\qquad\qquad\qquad\qquad \:reactivity}\put(0.8,2.2){\large\sf Fe\qquad\qquad\quad\qquad Ferrous}\put(0.8,1.2){\large\sf Pb\qquad\qquad\qquad \: \:\: Lead}\put(0.8,0.2){\large\sf H\qquad\qquad\qquad \: \:Hydrogen}\put(0.8, - 0.6){\large\sf Cu\qquad\qquad\qquad \: Copper}\put(0.8, - 1.5){\large\sf Hg\qquad\qquad\qquad \: Mercury}\put(0.8, - 2.5){\large\sf Ag\qquad\qquad\qquad \: \:Silver}\put(0.8, - 3.5){\large\sf Au\qquad\qquad\qquad \: \: Gold\qquad\qquad\qquad\quad \: \: minimum reactivity}\put(9.3,8.2){\vector(0, - 2){12}}\end{picture}](https://tex.z-dn.net/?f=%5Csetlength%7B%5Cunitlength%7D%7B0.8%20cm%7D%5Cbegin%7Bpicture%7D%2820%2C15%29%5Cthicklines%5Cput%285%2C9.5%29%7B%5Clarge%20%7B%5Cboxed%7B%20%5Csf%7BReactivity%20%5C%3A%20%20series%7D%7D%7D%7D%5Cput%280.8%2C8%29%7B%5Clarge%5Csf%20K%20%5Cqquad%5Cqquad%5Cqquad%20Potassium%5Cqquad%5Cqquad%5Cqquad%20%5C%3A%20maximum%7D%5Cput%280.8%2C7.2%29%7B%5Clarge%5Csf%20Na%20%5Cqquad%5Cqquad%5Cqquad%20Sodium%5Cqquad%5Cqquad%5Cqquad%5Cquad%20%5C%3A%20reactivity%7D%5Cput%280.8%2C6.2%29%7B%5Clarge%5Csf%20Ca%5Cqquad%5Cqquad%5Cqquad%20%5C%3A%20Calcium%7D%5Cput%280.8%2C5.2%29%7B%5Clarge%5Csf%20Mg%5Cqquad%5Cqquad%5Cquad%20%5C%3A%20Magnesium%7D%5Cput%280.8%2C4.2%29%7B%5Clarge%5Csf%20Al%5Cqquad%5Cqquad%5Cqquad%20%5C%3A%20Aluminium%5Cqquad%5Cqquad%5Cqquad%20%5C%3A%20decreasing%7D%5Cput%280.8%2C3.2%29%7B%5Clarge%5Csf%20Zn%5Cqquad%5Cqquad%5Cquad%5Cqquad%20%5C%3A%20Zinc%5Cqquad%5Cqquad%5Cqquad%5Cqquad%20%5C%3Areactivity%7D%5Cput%280.8%2C2.2%29%7B%5Clarge%5Csf%20Fe%5Cqquad%5Cqquad%5Cquad%5Cqquad%20Ferrous%7D%5Cput%280.8%2C1.2%29%7B%5Clarge%5Csf%20Pb%5Cqquad%5Cqquad%5Cqquad%20%5C%3A%20%5C%3A%5C%3A%20Lead%7D%5Cput%280.8%2C0.2%29%7B%5Clarge%5Csf%20H%5Cqquad%5Cqquad%5Cqquad%20%5C%3A%20%20%5C%3AHydrogen%7D%5Cput%280.8%2C%20-%200.6%29%7B%5Clarge%5Csf%20Cu%5Cqquad%5Cqquad%5Cqquad%20%5C%3A%20Copper%7D%5Cput%280.8%2C%20-%201.5%29%7B%5Clarge%5Csf%20Hg%5Cqquad%5Cqquad%5Cqquad%20%5C%3A%20Mercury%7D%5Cput%280.8%2C%20-%202.5%29%7B%5Clarge%5Csf%20Ag%5Cqquad%5Cqquad%5Cqquad%20%5C%3A%20%5C%3ASilver%7D%5Cput%280.8%2C%20-%203.5%29%7B%5Clarge%5Csf%20Au%5Cqquad%5Cqquad%5Cqquad%20%5C%3A%20%5C%3A%20%20Gold%5Cqquad%5Cqquad%5Cqquad%5Cquad%20%5C%3A%20%20%5C%3A%20minimum%20reactivity%7D%5Cput%289.3%2C8.2%29%7B%5Cvector%280%2C%20-%202%29%7B12%7D%7D%5Cend%7Bpicture%7D)
Answer:
<em>The N given in the question is normality while the M given in the question designates morality.
</em>
Explanation:
There are minor differences between both the terms normality and morality given in the question and both are inter convertible.
When one litre of solution is considered when the particles of solute in that litre would show the morality of the solution while when one litre of Solution is considered and equivalent are given then it is known as normality.