Answer:
Answers are in the explanation.
Explanation:
- The half‑life of A increases as the initial concentration of A decreases. order: <em>2. </em>In the half-life of second-order reactions, the half-life is inversely proportional to initial concentration.
- A three‑fold increase in the initial concentration of A leads to a nine‑fold increase in the initial rate. order: <em>2. </em>The rate law of second-order is: rate = k[A]²
- A three‑fold increase in the initial concentration of A leads to a 1.73‑fold increase in the initial rate. order: <em>1/2. </em>The rate law for this reaction is: rate = k √[A]
- The time required for [A] to decrease from [A]₀ to [A]₀/2 is equal to the time required for [A] to decrease from [A]₀/2 to [A]₀/4. order: <em>1. </em>The concentration-time equation for first-order reaction is: ln[A] = ln[A]₀ - kt. That means the [A] decreasing logarithmically.
- The rate of decrease of [A] is a constant. order: <em>0. </em>The rate law is: rate = k -<em>where k is a constant-</em>
Answer:
11.5moles of oxygen gas
Explanation:
The reaction equation is shown below;
C₂H₆O + 3O₂ → 2CO₂ + 3H₂O
We were given 11.5moles of H₂O produced;
Since the equation is balanced;
3 mole of oxygen gas was used to produce 3 mole of water
11.5 moles of water will be produced = 11.5moles of oxygen gas
<u>Answer:</u> The value of for the net reaction is 13.94
<u>Explanation:</u>
The given chemical equations follows:
<u>Equation 1:</u>
<u>Equation 2:</u>
The net equation follows:
As, the net reaction is the result of the addition of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the inverse of second equilibrium constant.
The value of equilibrium constant for net reaction is:
We are given:
Putting values in above equation, we get:
Hence, the value of for the net reaction is 13.94
The final temperature of the block of brass with a mass of 30.6 g at 87.4°C is 30.82°C.
SPECIFIC HEAT CAPACITY:
- The amount of heat absorbed or released by a substance can be calculated using the following formula:
- (m × c × ∆T) water = - (m × c × ∆T) metal
According to this question;
METAL:
- m = 30.6g
- c = 0.380 J/g°C
- ∆T = T - 87.4°C
WATER:
- m = 62.3g
- c = 4.184J/g°C
- ∆T = T - 28.3°C
- 62.3 × 4.184 × (T - 28.3) = - {30.6 × 0.380 × (T - 87.4)}
- 260.7T - 7376.8 = - {11.63T - 1016.3}
- 260.7T - 7376.8 = -11.63T + 1016.3
- 260.7T + 11.63T = 1016.3 + 7376.8
- Therefore, the final temperature of the block of brass with a mass of 30.6 g at 87.4°C is 30.82°C.
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Answer:asdfcgvvvvvvvvvvvvvvvbhj
Explanation: