How does the current in a circuit change if the resistance is doubled? The current is halved. The current is doubled. The curren
2 answers:
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Answer:
a)
b)
Explanation:
a) Let's use the constant velocity equation:
- v is the speed of the muon. 0.9*c
- c is the speed of light 3*10⁸ m/s
b) Here we need to use Lorentz factor because the speed of the muon is relativistic. Hence the time in the rest frame is the product of the Lorentz factor times the time in the inertial frame.
v is the speed of muon (0.9c)
Therefore the time in the rest frame will be:
No we use the value of Δt calculated in a)
I hope it helps you!