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miss Akunina [59]
3 years ago
6

Which explanations provide support for continental drift theory? Check all that apply.

Physics
1 answer:
denis23 [38]3 years ago
8 0
<h3><u>Full Question:</u></h3>

Which explanations provide support for continental drift theory? Check all that apply.

Dinosaurs lived on many continents.

Coal fields match up across continents.

Tropical plant fossils were found in Arctic areas.

Similar rock types are found across continents.

Evidence of glaciers can be found in South Africa.

Coal fields match up across continents.

Similar rock types are found across continents.

Tropical plant fossils were found in Arctic areas.

Evidence of glaciers can be found in South Africa.

<h3><u>Explanation:</u></h3>

The way the continents on the earth shifts its position is explained by the Continental drift theory. Alfred Wegener was the one who fist proposed this theory in 1912. This theory also explains how similar rocks are formed on the different continents and also  the reason why some of the animal and plant fossils looks similar.

The evidences that supports the continental drift theory can be Coal fields match up across continents. Fossils of Glossopteris supports the  theory of continental drift with coal fields  and coastlines . The land features, climate changes are some of the evidences that also supports the theory of continental drift.The evidences of the glaciers that can be found in South Africa also supports the explanation of the continental drift.

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Crazy boy [7]

Answer:

HEAT GENERATED FROM THE INTERIOR OF THE  EARTH IS CALLED GEOTHERMAL ENERGY.

Explanation:

THE TEMPERATURE IN THE INTERIOR OF THE EARTH RISES STEADILY AS WE GO DEEPER.SOMETIMES THIS HEAT ENERGY MAY SURFACE ITSELF IN THE FORM OF HOT SPRINGS ..THIS HEAT ENERGY CAN BE USED TO GENERATE POWER.

5 0
3 years ago
a baseball is hit 3 feet above ground level at 100 feet per second and at an angle of 45 with respect to the ground. (g=32 feet/
LiRa [457]

Answer:

hmax=81ft

Explanation:

Maximum height of the object is the highest vertical position along its trajectory.

The vertical velocity is equal to 0 (Vy = 0)

0=V_{y}-g*t=v_{0}*sin(\alpha)-g*th\\

we isolate th (needed to reach the maximum height hmax)

th = \frac{v_{0}*sin(\alpha)}{g}

The formula describing vertical distance is:

y = Vy * t-g* t^{2} / 2

So, given y = hmax and t = th, we can join those two equations together:

hmax = Vy* th-g*th^{2}/2

hmax =Vo^{2}*sin(\alpha )^{2}/(2*g)

if we launch a projectile from some initial height h all you need to do is add this initial elevation

hmax =h+Vo^{2}*sin(\alpha)^{2}/(2*g)

hmax =3+100^{2}*sin(45)^{2}/(2 * 32)=81 ft

6 0
3 years ago
Volume of an block is 5 cm3. If the density of the block is 250 g/cm3, what is the mass of the block ?​
9966 [12]

Answer:

1.25kg

Explanation:

Simply multiply volume and density together

4 0
3 years ago
Sound waves are mechanical waves. Which statement is true for this type of wave?
Bad White [126]

Answer:

Electromagnetic waves do not require a medium in order to transport their energy. Mechanical waves are waves that require a medium in order to transport their energy from one location to another. ... Sound is a mechanical wave and cannot travel through a vacuum.

6 0
3 years ago
A circular cross section, d = 25 mm, experiences a torque load, T = 25 N·m, and a shear force, V = 85 kN. Calculate the shear st
Maru [420]

Answer:

The correct answer is 231 Mpa i.e option a.

Explanation:

using the equation of torsion we Have

\frac{T}{I_{p}}=\frac{\tau }{r}\\\\\therefore \tau =\frac{T}{I_{p}}\times r

where,

\tau= shear stress at a distance 'r' from the center

T = is the applied torque

I_{p} = polar moment of inertia of the section

r = radial distance from the center

Thus we can see that if a point is located at center i.e r = 0 there will be no shearing stresses at the center due to torque.

We know that in case of a circular section the maximum shearing stresses due to a shear force occurs at the center and equals

\tau _{max}=\frac{4}{3}\times \frac{V}{A}

Applying values we get

\tau _{max}=\frac{4}{3}\times \frac{85\times 10^{3}}{0.25\times \pi \times (25\times 10^{-3})^{2}}\\\\\therefore \tau _{max}=230.88Mpa\approx 231Mpa

3 0
3 years ago
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