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3 years ago

What is the power of 4ohm resistor connected to a 12v battery?

Physics

2 answers:

NemiM [27]3 years ago

8 0

Answer:

36watts

Explanation:

Data obtained from the question include:

R (Resistor) = 4 Ohms

V (Voltage) = 12V

P (power) =?

P = IV

Recall: I = V/R

P = V^2 /R

P = (12)^2 /4

P = 144/4

P = 36watts

Therefore, power is 36watts

DochEvi [55]3 years ago

8 0

Answer:

= 36 watts

Explanation:

Power = I V

From ohms law

V = I R

divide both sides by R

V/R = I

I = V/R

therefore if, P = IV, put I = V/R into it

P= V/R × V

P = V² / R

Given, V = 12v

R = 4 ohms

Therefore

P= 12² / 4

P = 144/4

P = 36 watts

Power = 36 watts

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What is the IMA of a two-gear system if the resistance gear has 54 teeth and the effort

Dafna1 [17]

Answer:

IMA = 2

Explanation:

Given the following data;

Resistance gear = 54 teeth

Effort gear = 23 teeth

To find the ideal mechanical advantage (IMA);

IMA = number of teeth on the resistance gear/number of teeth on the effort gear

Substituting into the equation, we have;

IMA = 54/23

IMA = 2.35 ≈ 2

Therefore, the ideal mechanical advantage (IMA) of this two-gear system is 2.

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3 years ago

Mashcka [7]

Answer:

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3 years ago

A runner circles the track exactly 2 times for distance of 800m. it takes 4.0min. what is her average speed in m/s? what is her

Sindrei [870]

If the runner ends where she started, then her total displacement is $\Delta x=0\,\mathrm m$ , which means her average velocity will be

$\bar v=\dfrac{\Delta x}{\Delta t}=\dfrac{0\,\mathrm m}{4.0\,\mathrm{min}\cdot\frac{60\,\mathrm s}{1\,\mathrm{min}}=0\,\dfrac{\mathrm m}{\mathrm s}$

The total distance she traversed, however, was $\Delta d=800\,\mathrm m$ , which gives her an average speed of

$\bar s=\dfrac{\Delta d}{\Delta t}=\dfrac{800\,\mathrm m}{4.0\,\mathrm{min}\cdot\frac{60\,\mathrm s}{1\,\mathrm{min}}=3.3\,\dfrac{\mathrm m}{\mathrm s}$

5 0

4 years ago

A supertanker filled with oil has a total mass of 6.1 x108 kg. If the dimensions of the ship are those of a rectangular box 300

IrinaVladis [17]

Answer:

The bottom of the sea is 25 m below sea level.

Explanation:

Given data

Mass = 6.1 × $10^{8} \ kg$

$\rho_{sea} = 1020\ \frac{kg}{m^{3} }$

We know that Buoyant force on the tank is equal to gravity force of the tank.

$F_B = F_g$

$(\rho_{Fluid}) (g) (V_{disp}) = m g$

$(\rho_{Fluid}) (V_{disp}) = m$

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$V_{disp}$ = 598039.21 $m^{3}$

We know that

$V_{disp}$ = W × L × H

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Therefore the bottom of the sea is 25 m below sea level.

7 0

4 years ago

A boat radioed a distress call to a Coast Guard station. At the time of the call, a vector A from the station to the boat had a

VashaNatasha [74]

Answer:

d = 39.7 km

Explanation:

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$r_1 = 45 sin15 \hat i + 45 cos15 \hat j$

$r_1 = 11.64 \hat i + 43.46\hat j$

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so we have

$r_2 = 30 cos15\hat i + 30 sin15 \hat j$

$r_2 = 28.98\hat i + 7.76 \hat j$

now the displacement of the boat is given as

$d = r_2 - r_1$

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so the magnitude is given as

$d = \sqrt{17.34^2 + 35.7^2}$

$d = 39.7 km$

4 0

3 years ago