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WARRIOR [948]
3 years ago
11

Winds are named based on different factors. How are winds usually named?

Physics
1 answer:
eduard3 years ago
4 0
Winds are named based on which compass direction the wind is blowing. For example some common ones are NE or N or SE or SW. NE stands for Northeast, N for North, SE for South East and SW for Southwest.
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How long would this acceleration last
Aleksandr-060686 [28]
It would last as long as the applied force continued, or until the accelerating object hit something.
6 0
3 years ago
The charges Q1=Q and Q2=4Q that are a distance d apart, repel each other with a force of 1.60 N. What would be the force between
gladu [14]

Answer:

50.4 N

Explanation:

Q1 = Q

Q2 = 4 Q

Distance = d

The force is given by

F = \frac{KQ_{1}Q_{2}}{d^{2}}

1.60 = \frac{4KQ^{2}}{d^{2}}    .... (1)

Now,

Q3 = 2 Q

Q4 = 7 Q

distance = d/3

F' = \frac{9KQ_{3}Q_{4}}{d^{2}}

F' = \frac{126KQ^{2}}{d^{2}}   .... (2)

Divide equation (2) by equation (1), we get

F' / 1.60 = 126 / 4

F' = 50.4 N

Thus, the force is 50.4 N.

7 0
3 years ago
HELP PLEASE!!! 30+ points!!
GarryVolchara [31]

1) 9.26 cm

Explanation:

The focal length of a plane mirror is virtually infinite. Considering the lens equation,

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where f is the focal length, p is the object distance, q the image distance. If we replace f with infinity, we get

q=-p

The magnification equation states that

y' = -\frac{q}{p}y

where y is the size of the object and y' the size of the image. Substituting q=-p, we get

y'=y

this means that the image produced by a plane mirror is always:

- Upright (y' is positive)

- The same size as the object

In this case, we have a book of height 9.26 cm (y=9.26 cm). This means that the magnitude of the size of the image (y') will be 9.26 cm as well.

2) 22.7 cm

As we said before, due to the infinite focal length of a plane mirror,

q=-p

this means that the image produced by a plane mirror is always:

- Virtual (because q is negative)

- At the same distance from the mirror as the object

In this case, we have a book placed at 22.7 cm from the mirror (p=22.7 cm). This means that the magnitude of the distance of the image from the mirror (q) will be 22.7 cm as well.

3) 1.60 m/s

We said previously that the image produced by a plane mirror is always at the same distance from the mirror as the real object. This implies that whenever we move the object toward/away from the mirror, the distance p will alway remain equal to the distance q. But this also means that the object and the distance are moving toward/away from the mirror at the same speed.

Therefore, since in this case the person is moving away from the mirror at 1.60 m/s, the image will also move away at a speed of 1.60 m/s.

4 0
3 years ago
What do you do if you approach a railroad crossing with a crossbuck sign that has no lights or gates
miv72 [106K]
Proceed with caution before crossing
3 0
4 years ago
(i) Calculate the energy, in electron volts, of a photon whose frequency is (a) 620 THz}, (b) 3.10GHz , and(c) 46.0 MHz
DedPeter [7]

The energy in electron volts of the photons that has the following frequencies is as follows:

  1. 620 THz = 2.564eV
  2. 3.10GHz = 1.28 × 10-⁵eV
  3. 46.0 MHz = 1.902 × 10-⁷eV

<h3>How to calculate energy?</h3>

The energy of a photon can be calculated using the following formula:

E = hf

Where;

  • E = energy
  • h = Planck's constant (6.626 × 10-³⁴ J/s)
  • f = frequency

First, we convert the frequencies to hertz as follows;

  • 620THz = 6.2 × 10¹⁴Hz
  • 3.10GHz = 3.1 × 10⁹Hz
  • 46.0MHz = 4.6 × 10⁷Hz

  1. E = 6.626 × 10-³⁴ × 6.2 × 10¹⁴ = 2.564eV
  2. E = 6.626 × 10-³⁴ × 3.1 × 10⁹ = 1.28 × 10-⁵eV
  3. E = 6.626 × 10-³⁴ × 4.6 × 10⁷ = 1.902 × 10-⁷eV

Learn more about energy of a photon at: brainly.com/question/2393994

#SPJ1

6 0
2 years ago
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