Answer:
I think It Should be Star B
Explanation:
Answer:
The velocity in duct is 73.854 m/s.
Explanation:
Given that Pitot tube measuring velocity v in 50 cm diameter duct contain air of density 1.1 
.
Also, P1 = Pressure in duct is 97kpa and P2 = Pressure at impact or stagnation point is 100kpa.
Using Bernoulli equation,
When air is flowing through duct,
When air is at stagnation point.
Comparing both the equation,
v=73.854 m/s.
Therefore, The velocity in duct is 73.854 m/s.
Answer:1834.56 joules
Explanation:
Distance=36m
Coefficient of friction=0.2
Mass=26kg
Acceleration due to gravity=9.8m/s^2
Reaction=mass x acceleration due to gravity
Reaction=26 x 9.8
Reaction=254.8N
Coefficient of friction=frictional force ➗ reaction
0.2=frictional force ➗ 254.8
Frictional force=0.2 x 254.8
Frictional force=50.96N
work=friction force x distance
Work=50.96 x 36
Work=1834.56
Work=1834.56 joules
Answer:
v = 30.39 m/s
Explanation:
given,
mass of glider,M = 680 Kg
mass of the skydiver, m = 68 Kg
horizontal velocity,V = 30 m/s
when skydiver releases, velocity,v = 30 m/s
velocity if the glider,v' = ?
use the conservation of momentum
M V = m' v' + m v
m' = 680-68 = 612 Kg
680 x 30 = 612 x v + 60 x 30
612 v = 18600
v = 30.39 m/s
since the skydiver's speed will be the same as before release
The glider should continue to travel at 30.39 m/s since there are no external forces acting on it
