Grayson: 35h + 35 = y
Ian: 45h + 15 = y
(Substituting first hour in h)
35h + 35 = y
35(1) + 35
y = 70$ in the first hour for Grayson
45h + 15 = y
45(1) + 15
y = 60$ in the first hour for Ian
Grayson charges > Ian charges
(Substituting second hour in h)
35h + 35 = h
35(2) + 35
105$ in the second hour for Grayson
45h + 15 = h
45(2) + 15
135$ in the second hour for Ian
Grayson charges < Ian charges
Answer:
In the first hour Grayson charges more than Ian.
Answer:
C, 11.62 units
Step-by-step explanation:
tan 54° = 
x tan 54° = 16
x = 
x≈11.62468045
x= 11.62
Answer:
3x^2+1.5x-9
Step-by-step explanation:
(f+g) (x)
=f(x)+g(x)
=x/2-3+3x^2+x-6
=3x^2+1.5x-9
Answer:
18
Step-by-step explanation:
You plug in 2 hours as your x value. You get 4(2) + 10 = 18.
