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rusak2 [61]
3 years ago
13

Which type of box will best protect a fragile object by minimizing the force on the object

Physics
1 answer:
myrzilka [38]3 years ago
4 0
There is not picture or anything what are the answer choices?
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Calculate the decrease in gravitational potential energy of the ball as it moves down through the 0.90m the mass of the ball is
icang [17]

Answer:

G.P.E = 5.292 Joules

Explanation:

Given the following data;

Mass = 0.6 kg

Height = 0.9 m

To find the gravitational potential energy;

Gravitational potential energy (GPE): it is an energy possessed by an object or body due to its position above the earth.

Mathematically, potential energy is given by the formula;

G.P.E = mgh

Where,

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

But we know that acceleration due to gravity is equal to 9.8m/s²

G.P.E = 0.6*9.8*0.9

G.P.E = 5.292 Joules

8 0
3 years ago
Opposite chargers and like charges
cluponka [151]
Opposite charges attract
Like charges repel
7 0
4 years ago
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Which type of electromagnetic radiation is most likely to be ionizing
zlopas [31]

Answer:

Xrays. i hope that helps

Explanation:

4 0
3 years ago
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The force it would take to accelerate an 900-kg car at the rate of 6m/s2
tino4ka555 [31]

It would be 5,400N. I hope this helps!

3 0
4 years ago
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Can a goalkeeper at her/ his goal kick a soccer ball into the opponent’s goal without the ball touching the ground? The distance
PSYCHO15rus [73]

Answer:

No she cannot.

Explanation:

Let v_h be the horizontal component of the ball velocity when it's kicked, assume no air resistance, this is a constant. Also let v_v be the vertical component of the ball velocity, which is affected by gravity after it's kicked.

The time it takes to travel 95m accross the field is

t = 95 / v_h or v_h = 95/t

t is also the time it takes to travel up, and the fall down to the ground, which ultimately stops the motion. So the vertical displacement after time t is 0

s = v_vt + gt^2/2= 0

where g = -9.8m/s2 in the opposite direction with v_v

v_vt - 4.9t^2 = 0

v_vt = 4.9t^2

v_v = 4.9t

Since the total velocity that the goal keeper can give the ball is 30m/s

v = v_v^2 + v_h^2 = 30^2 = 900

(4.9t)^2 + \left(\frac{95}{t})^2 = 900

24.01t^2 + \frac{9025}{t^2} = 900

Let substitute x = t^2 > 0

24.01 x + \frac{9025}{x} = 900

We can multiply both sides by x

24.01 x^2 + 9025 = 900x

24.01x^2 - 900x + 9025 = 0

t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

t= \frac{900\pm \sqrt{(-900)^2 - 4*(24.01)*(9025)}}{2*(24.01)}

As (-900)^2 - 4*24.01*9025 = -56761 < 0

The solution for this quadratic equation is indefinite

So it's not possible for the goal keeper to do this.

6 0
3 years ago
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