Answer:
Explanation: the tempure range is 1,400
The sphere will go up until all the initial kinetic energy be transformed into potential energy.
Intital kinetic energy = m*(vi)^2 / 2
Final potential energy = mgh
mgh = m(vi)^2 / 2 => h = (vi)^2 / (2g)
g = 9.81 m/s^2
vi = (1.5m/s)^2
h = (1.5m/s)^2 / (2*9.81m/s)^2 = 0.115 m
The range is the distance run over the ramp
Using trigonometry, sin(20°) = h /run => run = h / sin(20) = 0.115m / sin(20) = 0.336 m
Answer: 0.336 m
Answer:
The answer to your question is:
a) t = 3.81 s
b) vf = 37.4 m/s
Explanation:
Data
height = 71.3 m = 234 feet
t = 0 m/s
vf = ?
vo = 0 m/s
Formula
h = vot + 1/2gt²
vf = vo + gt
Process
a)
h = vot + 1/2gt²
71.3 = 0t + 1/2(9.81)t²
2(71.3) = 9,81t²
t² = 2(71.3)/9.81
t² = 14.53
t = 3.81 s
b)
vf = 0 + (9.81)(3.81)
vf = 37.4 m/s
Answer:
(a). The horizontal and vertical components are and
(b). The horizontal and vertical components of the rocket's impact velocity is 150 m/s and 259.8 m/s.
Explanation:
Given that,
Angle = 60°
Speed = 300 m/s
(a). We need to draw the vector representing the rocket's impact and its components
Using given data
The components of rocket's impact
The horizontal component is
The vertical component is
(b). We need to calculate the horizontal and vertical components of the rocket's impact velocity
Using horizontal and vertical components
The horizontal component is
Put the value into the formula
The vertical component is
Put the value into the formula
Hence, (a). The horizontal and vertical components are and
(b). The horizontal and vertical components of the rocket's impact velocity is 150 m/s and 259.8 m/s.