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3 years ago

Resolve the factors ( xy+z)^2 (y-xz)^2

Mathematics

2 answers:

skelet666 [1.2K]3 years ago

5 0

Answer:

=x4y2z2−2x3y3z+2x3yz3+x2y4−4x2y2z2+x2z4+2xy3z−2xyz3+y2z2

Make me brainliest

BlackZzzverrR [31]3 years ago

5 0

Answer:

x2y-x2z-xy2+xz2+y2z-yz2

step by step

step.1

Equation at the end of step 1:(((x2)•(y-z)(+((y2)•(z-x)))+z2•(x-y)

step2

Equation at the end of step2

(((x2)•(yz))+yz•(z-x))+z2•(x-y)

step.3

equation at the end of step 3.

(x2•(y-z)+y2•(z-x))+z2•(x-y)

step4

trying to factor by pulling out:

factoring: x2y-x2z-xy2+xz2+y2z-yz2

thought fully split the expression at hand into groups,each group having two terms:

group1: y2z-yz2

group 2: x2y-x2z

group 3: xz2-yz2

pull out from each groups separately:

group 1:(x-z)•(-y2)

group 2:(y-z)•(x2)

group 3:(x-y)•(z2)

looking for common sub-expressions:

group 1:(x-z)•(-y2)

group 2:(y-z)•(x2)

group 3:( x-y)•(z2)

bad news !! factoring by pulling out fails:

The groups have no common factor and cannot be added up to form a multiplication.

final result:

x2y-x2z-xy2+xz2+y2z-yz2

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