Answer:
a) 19.2 s
b) No
Explanation:
Given:
v₀ = 125 m/s
a = -6.5 m/s²
v = 0 m/s
a) Find: t
v = at + v₀
(0 m/s) = (-6.5 m/s²) t + (125 m/s)
t ≈ 19.2 s
b) Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (125 m/s)² + 2 (-6.5 m/s²) Δx
Δx ≈ 1200 m
An aircraft carrier that's 850 meters long won't be long enough.
Answer:
1.5 m/s
Explanation:
Momentum is conserved and conservation of momentum is
p₁ + p₂ = p'₁ + p'₂
or
m₁v₁ + m₂v₂ = m₁v'₁ + m₂v'₂
In our problem, after collision v'₁ will be equal to v'₂.
Since objects are identical m₁ = m₂
m(v₁+ v₂) = 2m x v'₁
(2m/s + 1m/s) = 2v'₁
v'₁ = v'₂ = 1.5 m/s
Answer:
v = √ 2 G M/
Explanation:
To find the escape velocity we can use the concept of mechanical energy, where the initial point is the surface of the earth and the end point is at the maximum distance from the projectile to the Earth.
Initial
Em₀ = K + U₀
Final
= 
The kinetic energy is k = ½ m v²
The gravitational potential energy is U = - G m M / r
r is the distance measured from the center of the Earth
How energy is conserved
Em₀ = 
½ mv² - GmM /
= -GmM / r
v² = 2 G M (1 /
– 1 / r)
v = √ 2GM (1 /
– 1 / r)
The escape velocity is that necessary to take the rocket to an infinite distance (r = ∞), whereby 1 /∞ = 0
v = √ 2GM /
Answer:
V = I×R
where -
V = potential difference across
I = current flowing in the circuit
R = Equivalent Resistance in the circuit
The amount of solid does not affect how you are describing the solid so a is the answer