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3 years ago

If we take away a lot of energy from a liquid what phase will it change to ?

Physics

1 answer:

DanielleElmas [232]3 years ago

8 0

The liquid would change to gas

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If it took 125 seconds to complete 5 wave cycles, what is the period of the wave?

finlep [7]

The period of the wave is 25 s

Explanation:

To find the period of the wave, we have the formula

T= seconds/ no of cycle

T= 125/5

T= 25 s

The period of the wave is 25 s

4 0

4 years ago

A ball rolls off a level table with a speed of 2.2 m/s. The table is 1.2 meters high. How far away from the base of the table do

r-ruslan [8.4K]

The base of table is "1.08856 m" far away from the ball land.

Given:

Distance travelled by ball,

S = 1.2 m

Initial velocity,

u = 0 m/s

Acceleration,

a = 9.8 m/s²

Constant speed,

2.2 m/s

As we know the formula,

→ $S = ut+\frac{1}{2}at^2$

By substituting the values, we get

→ $1.2=\frac{1}{2}\times 9.8t^2$

→ $1.2 = 4.9 t^2$

→ $t = \sqrt{\frac{1.2}{4.9} }$

→ $= 0.4948 \ seconds$

Let,

Horizontal distance will be "x".
Time = t

→ $x = 2.2\times t$

$= 2.2\times 0.4948$

$= 1.08856 \ m$

Thus the solution above is right.

Learn more:

brainly.com/question/19170664

8 0

3 years ago

A 400g mass object at rest is acted on by a 200 N net force for 12 seconds. What is it’s final velocity?

Kisachek [45]

Explanation:

do we can say that the first step is finding the acceleration of the object. We do so by saying F = ma

so a = F/m

a = 500 m/s^2

we now have the time, acceleration and initial velocity.

so we can find the final velocity by using one of newtons equations which is: vf = vi + at

so:

vf = 0 + 500 × 12

vf = 6000

note that our initial velocity was zero since the object was initially at rest.

if you still have any doubt dont hesitate to ask for further help.

3 0

2 years ago

Write Newton's 3rd law. How would this law relate to a rocket ship taking off from the earth? Would this law affect the rocket s

irina1246 [14]

Answer:

Part A

Newton's 3rd law states that action and reaction are equal and opposite, mathematically, we have;

$F_A$ = - $F_B$

Where;

$F_A$ = The action force

$F_B$ = The reaction force

Part B

The law indicates that the force with which a rocket ship uses in taking off from the Earth, $F_A$ is equal in magnitude, and opposite in direction to the reaction force of the Earth to the motion of the rocket, (-) $F_B$

Part C

The law is a universal law, and it will also affect the rocket ship in space, as the force of the jet from the exhaust is directed towards Earth while in space, the rocket is propelled deeper into space

Explanation:

6 0

3 years ago

How do I solve using the formula: Vf^2=vo^2+2gh ^2 means square

PtichkaEL [24]

your second line ... minus 2gh ...

5 0

3 years ago