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3 years ago

7

If one face of a cube has an area of 6.75 square inches, what is the surface area of the entire cube?

1 answer:

Marianna [84]3 years ago

8 0

Answer:

33.75

Step-by-step explanation:

Brainiest?

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Simplify negative 3 over 2 / 9 over 6

Temka [501]

$\mathrm{Simplify} -\frac{3}2\div\frac{9}6.$

Dividing by a fraction is the same as multiplying by its reciprocal. (flipped version)

$-\frac{3}2\div\frac{9}6=-\frac{3}2\times\frac{6}{9}$

6 and 9 are both divisible by 3, so we can simplify 6/9 = 2/3.

$-\frac{3}2\times\frac{2}3$

We can multiply across right now, but we might as well cross cancel.
Look at the numbers diagonal from one another...-3 and 3 are both divisible by 3, so we can change them to -1 and 1...2 and 2 are both divisible by 2, so we can change them to 1 and 1...

$-\frac{1}1\times\frac{1}1$

Any fraction over 1 can just be expressed as a whole number.

$-1\times1$

Our final answer... $-\frac{3}2\div\frac{9}6=\boxed{-1}$

If you were to multiply across, (maybe you don't like cross cancelling, idk?) you'd get the same answer, of course.

$-\frac{3}2\times\frac{2}3=-\frac{6}6=\boxed{-1}$

6 0

3 years ago

Read 2 more answers

Solve the equation for the indicated variable 4=t-7s , for t

solong [7]

Answer:

t = 7s + 4

Step-by-step explanation:

The goal is to get t alone. So we should move 7s to the other side of the equals to sign. When we move 7s to the other side of the equals to sign the sign changes to -7s. There are no like terms to be collected so the answer should be 7s + 4 for t.

7 0

3 years ago

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if the equation of a parabola is y = 7(x-4)^2+v and its vertex is (4,-2) , what is the value of v in the equation

N76 [4]

The vertex form of a quadratic function: y = a(x - h)² + k

vertex (h; k)

We have: y = 7(x - 4)² + v
vertex: (4; -2)

therefore: v = -2

6 0

3 years ago

Lynn paid $17.25 for ribbon. The cost of the ribbon was $0.75 per foot. How many feet of ribbon did

snow_tiger [21]

Answer: 23

Step-by-step explanation:

1. Divide the amount Lynn paid for the ribbon, 17.25, by the amount the ribbon cost per foot, 0.75, to get how many feet of ribbon she bought.

17.25 / 0.75 = 23

7 0

2 years ago

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A rectangle has vertices E(4,8), F(2,8), G(2,-2) and H(-4,-2). The rectangle is dilated with the origin as the center of dilatio

Leona [35]

Note: The image of G after the dilation must be G'(5,-5) instead of G'(5,5).

Given:

The vertices of a rectangle are E(4,8), F(2,8), G(2,-2) and H(-4,-2).

The rectangle is dilated with the origin as the center of dilation so that G's is located at (5,-5).

To find:

The algebraic representation that represents this dilation.

Solution:

If a figure is dilated by factor k with origin as the center of dilation, then the dilation is defined as:

$(x,y)\to (kx,ky)$ ...(i)

Let the given rectangle is dilated by factor k with origin as the center of dilation. Then,

$G(2,-2)\to G'(k(2),k(-2))$

$G(2,-2)\to G'(2k,-2k)$

The image of G after dilation is G'(5,-5). So,

$(2k,-2k)=(5,-5)$

On comparing both sides, we get

$2k=5$

$k=\dfrac{5}{2}$

So, the scale factor is $k=\dfrac{5}{2}$ .

Substituting $k=\dfrac{5}{2}$ in (i), we get

$(x,y)\to \left(\dfrac{5}{2}x,\dfrac{5}{2}y\right)$

Therefore, the required algebraic representation to represents this dilation is $(x,y)\to \left(\dfrac{5}{2}x,\dfrac{5}{2}y\right)$ .

3 0

3 years ago