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zysi [14]
3 years ago
10

A beaker contains 318 mL

Chemistry
1 answer:
katovenus [111]3 years ago
5 0

Answer:

3.97 M

Explanation:

Given data:

Initial volume V₁  = 318 mL

Initial molarity M₁ = 5.75 M

New volume V₂=  461 mL

New concentration M₂= ?

Solution:

New volume V₂= 143 mL+ 318 mL

New volume V₂= 461 mL

Formula:

M₁V₁  = M₂V₂

M₂ = M₁V₁ / V₂

M₂ = 5.75 M × 318 mL / 461 mL

M₂ = 1828.5 M. mL/ 461 mL

M₂ = 3.97 M

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