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zysi [14]
3 years ago
10

A beaker contains 318 mL

Chemistry
1 answer:
katovenus [111]3 years ago
5 0

Answer:

3.97 M

Explanation:

Given data:

Initial volume V₁  = 318 mL

Initial molarity M₁ = 5.75 M

New volume V₂=  461 mL

New concentration M₂= ?

Solution:

New volume V₂= 143 mL+ 318 mL

New volume V₂= 461 mL

Formula:

M₁V₁  = M₂V₂

M₂ = M₁V₁ / V₂

M₂ = 5.75 M × 318 mL / 461 mL

M₂ = 1828.5 M. mL/ 461 mL

M₂ = 3.97 M

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Consider the above unbalanced equation. What volume of CO2 is produced at 270. mm Hg and 38.5°C when 0.820 g of C4H8 reacts with
irinina [24]

Answer:

The volume of CO2 is 4.20 L

Explanation:

Step 1: Data given

Pressure = 270 mm Hg =  260 /760 = 0.355263 atm

Temperature : 38.5 °C = 311.65 K

Mass of C4H8 = 0.820 grams

Step 2: The balanced equation

C4H8 + 6O2 → 4CO2 + 4H2O

Step 3: Calculate moles C4H8

Moles C4H8 = mass C4H8 / molar mass C4H8

Moles C4H8 = 0.820 grams / 56.11 g/mol

Moles C4H8 = 0.0146 moles

Step 4: Caalculate moles CO2

For 1 mol C4H8 we need 6 moles O2 to produce 4 moles CO2 and 4 moles H2O

For 0.0146 moles we'll have 4*0.0146 = 0.0584 moles CO2

Step 6: Calculate Volume CO2

p*V = n*R*T

V = (n*R*T) /p

⇒ with V = the volume of CO2 = TO BE DETERMINED

⇒ with n = the moles of CO2 = 0.0584 moles

⇒ with R = the gas constant = 0.08206 L*atm / mol*K

⇒ with T = The temperature = 311.65 K

⇒ with p = the pressure = 0.355263 atm

V = (0.0584 * 0.08206 * 311.65) / 0.355263

V = 4.20 L

The volume of CO2 is 4.20 L

8 0
3 years ago
What is the highest occupied energy level for an atom of copper (Cu)? *
bonufazy [111]

Answer:

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hope this helps

8 0
3 years ago
Why do we have thumbs?
alexandr1967 [171]

Answer:

According to Goog|e, "As the thumb is opposable, <u>it allows people to position it against other digits of the hand to manipulate or hold an object</u>. Some evidence suggests that this ability makes the thumb responsible for roughly 40% of the hand functions."

Explanation:

I hope this helps!

5 0
3 years ago
Can someone plz help me on this. I need it really bad
kifflom [539]

Answer:

-  40.66

-  9.91

Explanation:

For the first question:

Our theoretical compound is MR₂

1 mol of MR₂ contains 1 mol of M and 2 moles of R

Let's find out the molar mass:

9.45 g/mol + 18.12 g/mol . 2 = 45.69 g/mol

We can solve this, by an easy rule of three:

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Then, 0.89 moles may weigh 40.66 g

For the second question:

Our theoretical compound is D₂G

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11.45 g/mol . 2 + 44.57 g/mol = 67.47 g/mol

1 mol of anything contains 6.02×10²³ molecules. By this definition we can say that 6.02×10²³ molecules weigh 67.47 grams. Let's solve by the rule of three:

6.02×10²³ molecules weigh 67.47 g

8.84×10²² molecules may weigh (8.84×10²² . 67.47 ) / 6.02×10²³ = 9.91 g

8 0
3 years ago
What is meant by the term specific heat?
Alex73 [517]

Answer:

the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).

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3 years ago
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