A 900-kg car traveling east at 15.0 m/s collides with a 750-kg car traveling north at 20.0 m/s. The cars stick together. What is
the speed of the wreckage just after the collision?
1 answer:
Answer:
12.2 m/s
Explanation:
Initial momentum = final momentum
In the x direction:
(900 kg) (15.0 m/s) = (900 kg + 750 kg) vx
vx = 8.18 m/s
In the y direction:
(750 kg) (20.0 m/s) = (900 kg + 750 kg) vy
vy = 9.09
The magnitude of the velocity is therefore:
v = √(vx² + vy²)
v = 12.2 m/s
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