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mixer [17]
3 years ago
5

A battery of internal resistance 1 Ω and emf of 12 volt connected to external resistance of 79 Ω.Calculate the power delivered b

y the battery to the circuit.
Physics
1 answer:
Masteriza [31]3 years ago
4 0

Answer:

<em>P = 1.8 Watt</em>

Explanation:

<u>Electromotive Force (EMF)</u>

It consists of a DC source ε with small internal resistance Ri. When it's connected to an external resistance Re a current i flows by the circuit whose value is given by:

\displaystyle i =\frac{\varepsilon }{R_i+R_e}

The internal resistance of the battery is Ri=1 ohm and its emf is ε=12 V. When connected to an external resistance of Re=79 ohm, the current is:

\displaystyle i =\frac{12}{1+79}=\frac{12}{80}

i = 0.15 A

The power delivered by the battery is:

P = ε.i

P = 12 V * 0.15 A

P = 1.8 Watt

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