Answer:
15mm
Step-by-step explanation:
we are looking for extension
To get Extension you need the original length and the strain both of which you are given
initial length L = 1.00m
the area A = 0.5mm² = 0.5 mm² = 0.5 x 10⁻⁶ m² ( we are changing to metres squared)
E = 2.0 x 10¹¹ n/m², Young's modulus
P = 1500N, the applied tension
Now to Calculate the stress.
σ = P/A (force/area) = (1500 N)/(0.5 x 10⁻⁶ m²) = 3 x 10⁹ N/m²
Also, Let β = the stretch of the string.
Then the strain is
ε = β/L (extension/ original length)
By definition, the strain is ε = σ/E = (3 x 10⁹ N/m²)/(2 x 10¹¹ N/m²) = 0.015
Therefore β/(1 m) = 0.015β = 0.015 m = 15 mm
Answer: 15 mm
Answer: the dog eats 68.76 lbs of food in 18 weeks
Step-by-step explanation: 3.82x 18=68.76
Answer:
No it does not
Step-by-step explanation:
Answer:
She has $128.65 left
Step-by-step explanation:
$257.29 x 1/4 = $64.32
$257.29 - $64.32 = $192.97
$192.97 x 1/3 = $64.32
$192.97 - $64.32 = $128.65
<u>BRAINLIEST PLEASEEE</u>
The arc length of the semicircle is 5π units
<h3>Calculating length of an arc</h3>
From the question, we are to calculate the arc length of the semicircle
Arc length of a semicircle = 1/2 the circumference of the circle
∴ Arc length of a semicircle = 1/2 × 2πr
Arc length of a semicircle = πr
Where r is the radius
From the given information,
r = 5
∴ Arc length of the semicircle = 5 × π
Arc length of the semicircle = 5π units
Hence, the arc length of the semicircle is 5π units
Learn more on Calculating length of an arc here: brainly.com/question/16552139
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