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3 years ago

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An irregular shape object has a mass of 19 oz. A graduated cylinder with and initial volume of 33.9 mL. After the object was dro

pped in the graduated cylinder, it had a volume of 92.8 mL. What is the density of object( g/mL)

1 answer:

madreJ [45]3 years ago

7 0

Explanation:

m = 19 oz × (28.3 g/1 oz) = 537.7 g

V = 92.8 mL

$\rho = \dfrac{m}{V}= \dfrac{537.7\:g}{92.8\:mL} = 5.79\:\frac{g}{mL}$

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Answer:

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Explanation:

The mathematical form of Ohms law is given by :

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Where V is voltage

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Answer:

a) $t=1.4\times 10^{-5}\ s$

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Explanation:

Given that

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a)

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b)

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So now by putting the values in equation 1

$a=\dfrac{E q}{m}$

$a=\dfrac{1.6\times 10^{-19}\times 0.027}{9.1\times 10^{-31}}\ m/s^2$

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Here initial velocity u= 0 m/s

$S= \dfrac{1}{2}\times 4.74\times 10^{9}\times (1.4\times 10^{-5})^2\ m$

S=0.464 m

S= 46.4 cm

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What would you do to improve the precision of an experiment?

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Explanation:

Precision represents that how close the different measurements of the sample one take are to one another.

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Answer:

a) time taken to catch up with speeding car is 12.25 secs

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Explanation:

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acceleration of police car = 10 mi/hr = 4.47 m/s²

$V_{f}$ = 70 mi/hr = 31.29 m/s

Now time taken to reach maximum speed is t₁

so

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we substitute

31.29 = 0 + 4.47t₁

t₁ = 31.29 / 4.47

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now

d₁ = 0 + 1/2 × at₁²

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we substitute

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Δd = $d_{c}$ - d₁

Δd = 156.46 - 109.5

Δd = 46.96 m

time taken to cover Δd will be

t₂ = Δd / ( $V_{f}$ - $V_{c}$ )

t₂ = 46.96 / ( 31.29 - 22.352 )

t₂ = 46.96 / 8.938

t₂ = 5.25 sec

distance travelled by the police in time t₂ will be

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d₂ = 31.29 × 5.25

d₂ = 164.3 m

a) How long will it take before the officer catches up to the speeding car;

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t = t₁ + t₂

t = 7 + 5.25

t = 12.25 secs

Therefore, time taken to catch up with speeding car is 12.25 secs

b) how far will it have travelled in order to do so;

distance = d₁ + d₂

distance = 109.5 + 164.3

distance = 273.8 m

Therefore, the police car will travel 273.8 m to catch up with the speeding car

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