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Mademuasel [1]
2 years ago
11

Ingrid is moving a box from the ground into the back of a truck. She uses 20 N of force to move the box 5 meters. If she uses an

inclined plane to reduce her force to 10 N which of the following statements will be true?
A. She will decrease the amount of work done.
B. She will make her work efficiency 100 percent.
C. She will increase the distance the box moves.
D. All of the above.
Physics
1 answer:
AVprozaik [17]2 years ago
7 0

<em>I</em><em> </em><em>think</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>o</em><em>f</em><em> </em><em>option</em><em> </em><em>A</em><em>.</em>

<em>Explanation</em><em>:</em>

<em>Inclined</em><em> </em><em>plane</em><em> </em><em>multiplies</em><em> </em><em>the</em><em> </em><em>applie</em><em>d</em><em> </em><em>effort</em><em>.</em><em>S</em><em>o</em><em>,</em><em>t</em><em>h</em><em>e</em><em> </em><em>for</em><em>c</em><em>e</em><em> </em><em>applied</em><em> </em><em>become</em><em> </em><em>less</em><em>.</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>

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3 years ago
A plane flies 1800 miles in 9 ​hours, with a tailwind all the way. the return trip on the same​ route, now with a​ headwind, tak
Fittoniya [83]

Initially its moving with tail wind so here the speed of wind will support the motion of the plane

so we can say

V_{plane} + v_{wind} = \frac{distance}{time}

V_{plane} + v_{wind} = \frac{1800}{9}

V_{plane} + v_{wind} = 200 mph

now when its moving with head wind we can say that wind is opposite to the motion of the plane

V_{plane} - v_{wind} = \frac{distance}{time}

V_{plane} - v_{wind} = \frac{1800}{12}

V_{plane} - v_{wind} = 150mph

now by using above two equations we can find speed of palne as well as speed of wind

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5 0
3 years ago
Suppose you increase your walking speed from 5 m/s to 14 m/s in a period of 3 s. What is your acceleration
kirza4 [7]
5-14 m/s in 3 seconds
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4 0
3 years ago
A(n) 7.7-kg object is sliding across the ice at 2.34 m/s in the positive x direction. An internal explosion occurs, splitting th
-BARSIC- [3]

Answer:

Average acceleration on first part of the chunk is given as

a_1 = 13.125 m/s^2

Average acceleration on second part of the chunk is given as

a_2 = -13.125 m/s^2

Explanation:

By momentum conservation along x direction we will have

mv_i = \frac{m}{2}v_1 + \frac{m}{2}v_2

so we have

v_1 + v_2 = 2v

v_1 + v_2 = 4.68

also by energy conservation

\frac{1}{2}(\frac{m}{2})v_1^2 + \frac{1}{2}(\frac{m}{2})v_2^2 - \frac{1}{2}mv^2 = 17 J

\frac{1}{4}m(v_1^2 + v_2^2) - \frac{1}{2}mv^2 = 17

(v_1^2 + v_2^2) - 2v^2 = \frac{4}{7.7}(17)

(4.68 - v_2)^2 + v_2^2 - 2v^2 = 8.83

21.9 + 2v_2^2 - 9.36 v_2 - 10.95 = 8.83

2v_2^2 - 9.36v_2 + 2.12 = 0

by solving above equation we will have

v_1 = 4.44 m/s

v_2 = 0.24 m/s

Average acceleration on first part of the chunk is given as

a_1 = \frac{4.44 - 2.34}{0.16}

a_1 = 13.125 m/s^2

Average acceleration on second part of the chunk is given as

a_2 = \frac{0.24 - 2.34}{0.16}

a_2 = -13.125 m/s^2

5 0
3 years ago
uniform ladder of length 6.0 m and weight 300 N leans against a frictionless vertical wall. The foot of the ladder isplaced 3.0
olganol [36]

Answer:

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This is also equal to the static force of friction that must be applied at the point of contact with the floor to balance forces in the x-direction.

Fx1 = Fx2 = 86.6 N

3 0
3 years ago
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