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2 years ago

Which number is the same distance as 10 from 0 on number line

Mathematics

2 answers:

mote1985 [20]2 years ago

8 0

Answer:

-10

Step-by-step explanation:

lakkis [162]2 years ago

7 0

Answer:

-10

Step-by-step explanation:

Absolute value, -10 is the same distance away from zero on a number line.

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The population in the current year is 31.5 million and the real GDP is $814 million. The previous year's statistics were a popul

andrew11 [14]

Answer:

The change in the standard of living, measured by growth in real GDP per person, is 0.1356%

Step-by-step explanation:

Given,

In the current year,

Population = 31.5 million,

Real GDP = $814 million,

So, the real GDP per person = $\frac{814}{31.5}$ ≈ 25.841

In the previous year,

Population = 31 million,

Real GDP = $800 million,

So, the real GDP per person = $\frac{800}{31}$ ≈ 25.806

Hence, change percentage = $\frac{\text{Change in GDP per person}}{\text{Previous year GDP per person}}\times 100$

$=\frac{25.841-25.806}{25.806}\times 100$

$=\frac{0.035}{25.806}\times 100$

$=\frac{3.5}{25.806}$

≈ 0.1356 %

5 0

2 years ago

tia_tia [17]

Answer:

$8-6i$

Step-by-step explanation:

Multiply out $(3-i)^2$ in order to find out which expression it is equivalent to.

1) Since the whole quantity is squared, write it out as $(3-i)(3-i)$ .

$(3-i)^2\\(3-i)(3-i)$

2) Multiply binomials by using the FOIL method. Multiply the terms that are listed first in each binomial, then the ones that are listed outermost when looking at both binomials, then innermost, and finally the last terms listed in each binomial. Simplify and combine like terms.

$(3-i)(3-i)\\9 - 3i - 3i + i^2$

$9 - 6i + i^2$

3) $i = \sqrt{-1}$ , so $i ^2$ must be $(\sqrt{-1} )(\sqrt{-1})$ . Thus, $i^2$ is equivalent to -1. Knowing this, simplify and combine like terms.

$9 - 6i + ((-\sqrt{1} )(\sqrt{-1} ))$

$9 - 6i -1\\8 - 6i$

Thus, it is equivalent to $8 - 6i$ .

6 0

3 years ago

What is the side length a in the triangle below?

grigory [225]

Answer:

a=5

Step-by-step explanation:

a^2+b^2=c^2

c^2-b^2=a^2

13^2-12^2=a^2

169-144=a^2

25=a^2

5=a

8 0

2 years ago

Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

7 0

2 years ago

During one snowy month a kentucky school held classes 9/11 of possible the school days if there are 22 possible school days how

SOVA2 [1]

This question isn't phrased correctly, but I will assume it's asking about common denominators with fractions.

9/11 1/22

18/22 1/22

18 school days.

5 0

3 years ago