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Allushta [10]
3 years ago
11

Please answer correctly !!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!

Mathematics
1 answer:
olga_2 [115]3 years ago
3 0

Answer:

2 \sqrt{15}

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ANTONII [103]

Answer:

sin B sin C. When this equation is combined with the previous equation, we obtain the Law of. Sines. ... ас. B. FIGURE 4.5 Solving an. ASA triangle. Keep in mind that we must be given one of the three ratios to apply the ...

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3 years ago
Special right triangles <br><br> Find the value of each missing variable
Shalnov [3]

Hi!

Rules for solving 30-60-90 triangles are as follows:

* The hypotenuse is double the short leg.

* The short leg times √3 is the long leg

To solve then, we divide 4√21 by √3 and get 4√7. That is x, and to get y we multiply by 2. That is 8√7.

Hope this helps! :D

6 0
3 years ago
Suppose the cost of college tuition is expected to increase 5% every year. How much will the tuition at a comunity college cost
evablogger [386]

Answer:

$7,596.43

Step-by-step explanation:

The cost of the college tuition is increasing 5% compounded annually for 5 years.

∴ A = P(1 + r%)ⁿ

where A = tuition fee after 5 years.

           P = current tuition

           r = rate of increase

            n = period

A =  $5,952(1 + 5%)⁵

     = $5,952(1 + 0.05)⁵

     =  $5,952 × 1.05⁵

     = $7,596.43

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8 0
3 years ago
Read 2 more answers
What number is mid way between 2/3 and 1
horsena [70]

5/6 is an answer to your question

6 0
3 years ago
Read 2 more answers
16. Let W be the set of all vectors in R3 of the form a+2b b -3a Find a basis for Wand state the dimension of W.
Yuki888 [10]

Answer:

W=\{\left[\begin{array}{ccc}a+2b\\b\\-3a\end{array}\right]: a,b\in\mathbb{R} \}

Observe that if the vector x=\left[\begin{array}{ccc}x\\y\\z\end{array}\right] is in W then it satisfies:

\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{c}a+2b\\b\\-3a\end{array}\right]=a\left[\begin{array}{c}1\\0\\-3\end{array}\right]+b\left[\begin{array}{c}2\\1\\0\end{array}\right]

This means that each vector in W can be expressed as a linear combination of the vectors \left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]

Also we can see that those vectors are linear independent. Then the set

\{\left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]\} is a basis for W and the dimension of W is 2.

7 0
3 years ago
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