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Korvikt [17]
3 years ago
6

(Level 5-6) 3. An object accelerates 15.0 m/s2 when a force of 8.ON is applied to it. What is the mass of the

Physics
1 answer:
VMariaS [17]3 years ago
5 0

Answer:

0.53 kg

Explanation:

Mass = \frac{Force}{acceleration}

Force (also weight) = 8.0N

Acceleration = 15.0 m/s^{2}

= \frac{8.0}{15}

= 0.53 kg ( to 2 decimal place )

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Manmade global warming is caused by what?
kirill [66]
Human activities is the main reason of global warming such as factories and cars that causes carbon dioxide , carbon monoxide and other toxic gases
4 0
3 years ago
2. While standing near a bus stop, a student hears a distant horn beeping. The frequency emitted by the horn is 440 Hz. The bus
jarptica [38.1K]

Given Information:

Frequency of horn = f₀ = 440 Hz

Speed of sound = v = 330 m/s

Speed of bus = v₀ = 20 m/s

Answer:

Case 1. When the bus is crossing the student = 440 Hz

Case 2. When the bus is approaching the student = 414.9 Hz

Case 3. When the bus is moving away from the student = 468.4 Hz

Explanation:

There are 3 cases in this scenario:

Case 1. When the bus is crossing the student

Case 2. When the bus is approaching the student

Case 3. When the bus is moving away from the student

Let us explore each case:

Case 1. When the bus is crossing the student:

Student will hear the same frequency emitted by the horn that is 440 Hz.

f = 440 Hz

Case 2. When the bus is approaching the student

f = f₀ ( v / v+v₀ )

f = 440 ( 330/ 330+20 )

f = 440 ( 330/ 350 )

f = 440 ( 0.943 )

f = 414.9 Hz

Case 3. When the bus is moving away from the student

f = f₀ ( v / v+v₀ )

f = 440 ( 330/ 330-20 )

f = 440 ( 330/ 310 )

f = 440 ( 1.0645 )

f = 468.4 Hz

6 0
3 years ago
Professional Application. A 96 kg football player catches a 0.900 kg ball with his feet off the ground with both of them moving
Zarrin [17]

To solve this problem it is necessary to apply the equations related to the conservation of momentum.

This definition can be expressed as

m_1u_1+m_2u_2 = (m_1+m_2)V_f

Where

m_{1,2} = Mass of each object

u_{1,2} = Initial Velocity of each object

V_f= Final velocity

Rearranging the equation to find the final velocity we have,

V_f = \frac{m_1u_1+m_2u_2}{(m_1+m_2)}

Our values are given as

m_1 = 96Kg\\m_2 = 0.9Kg\\u_1 = 6.3m/s\\u_2 = 27.4m/s

Replacing we have,

V_f = \frac{(96)(6.3)+(0.9)(27.4)}{(96+0.9)}

V_f = 6.4959m/s

Therefore the final velocity is 6.5m/s

3 0
3 years ago
Which action will increase the gravitational force between two objects?
schepotkina [342]
The answer is D have a nice day!
8 0
3 years ago
Read 2 more answers
At the top of a pole vault, an athlete actually can do work pushing on the pole before releasing it. Suppose the pushing force t
Salsk061 [2.6K]

Answer:

The work done on the athlete is approximately 2.09 J

Explanation:

From the definition of the work done by a variable force:

\displaystyle{\int_{x_i}^{x_j}F(x)dx}

and substituting with the function of our problem:

\displaystyle{\int_{0}^{0.19}(140x-190x^2)dx\approx2.09\mathrm{J}}

5 0
4 years ago
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