A small pebble would sink in water because it is to light and can’t hold itself up in the water. Hope this helped!
Sound waves require a medium. For example - think about space. there is no air or liquid because it is a vacuum, which is why sounds don’t travel through space.
Answer:
A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.
Explanation:
The bulk modulus is represented by the following differential equation:

Where:
- Bulk module, measured in pascals.
- Sample volume, measured in cubic meters.
- Local pressure, measured in pascals.
Now, let suppose that bulk remains constant, so that differential equation can be reduced into a first-order linear non-homogeneous differential equation with separable variables:

This resultant expression is solved by definite integration and algebraic handling:




The final volume is predicted by:

If
,
and
, then:


Change in volume due to increasure on pressure is:



A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.
Answer:
V is greater
Explanation:
because v intial at that time V final is the that speed which it is going at that time