Answer:
total distance = 1868.478 m
Explanation:
given data
accelerate = 1.68 m/s²
time = 14.2 s
constant time = 68 s
speed = 3.70 m/s²
to find out
total distance
solution
we know train start at rest so final velocity will be after 14 .2 s is
velocity final = acceleration × time ..............1
final velocity = 1.68 × 14.2
final velocity = 23.856 m/s²
and for stop train we need time that is
final velocity = u + at
23.856 = 0 + 3.70(t)
t = 6.44 s
and
distance = ut + 1/2 × at² ...........2
here u is initial velocity and t is time for 14.2 sec
distance 1 = 0 + 1/2 × 1.68 (14.2)²
distance 1 = 169.37 m
and
distance for 68 sec
distance 2= final velocity × time
distance 2= 23.856 × 68
distance 2 = 1622.208 m
and
distance for 6.44 sec
distance 3 = ut + 1/2 × at²
distance 3 = 23.856(6.44) - 0.5 (3.70) (6.44)²
distance 3 = 76.90 m
so
total distance = distance 1 + distance 2 + distance 3
total distance = 169.37 + 1622.208 + 76.90
total distance = 1868.478 m
Answer:
Following are the responses to these question:
Explanation:
Since the 
is the current of ckt which depend on the reactance which inductor that also enables the ckt and inductor resistance 
for capacities
for
When 
then
therefore, 
remains at the same so, the maximum current remains the in same ckt.
Answer: A hot lightbulb gave off white visible light instead of ultraviolet light.
Explanation:
Answer: B, increase the rate at which he turns the crank
Explanation: i got it right
Answer:
t = 1.659s
Explanation:
We can use the kinematics equations to solve this questions:
v = u + at
where v = Final Velocity, u = initial velocity, a = acceleration, t = time, s = displacement
a) Given information from the question,
u = 
(Convert km/h to m/s first)
a = 
s = 35m
Now we can substitute these values into the 2nd kinematics equation to find v, final velocity.
b) Now we have the final velocity, we can substitute the values into the first kinematics equation to find t , the time taken.
v = u + at
22.761 = 19.444 + 2t
2t = 22.761 - 19.444
t =
t = 1.659s
