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Crazy boy [7]
3 years ago
14

__________ is a developmental defect in which a portion of the spinal cord protrudes outside the vertebrae.

Physics
1 answer:
7nadin3 [17]3 years ago
3 0

Answer: Spina bifida

Explanation:

Spina bifida is a developmental defect in which a portion of the spinal cord protrudes outside the vertebrae.

Spina bifida is a birth defect that occurs when there is improper formation of the spine and spinal cord. It's a type of neural tube defect. The structure in a developing embryo that eventually becomes the baby's brain, spinal cord and the tissues that enclose them is the neutral tube.

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A violin string is 45.0 cm long and has a mass of 0.242 g. When tightened on the neck of the violin, the distance between the pi
stiks02 [169]

Answer:

The tension is 75.22 Newtons

Explanation:

The velocity of a wave on a rope is:

v=\sqrt{\frac{TL}{M}} (1)

With T the tension, L the length of the string and M its mass.

Another more general expression for the velocity of a wave is the product of the wavelength (λ) and the frequency (f) of the wave:

v= \lambda f (2)

We can equate expression (1) and (2):

\sqrt{\frac{TL}{M}}=\lambda f

Solving for T

T= \frac{M(\lambda f)^2}{L} (3)

For this expression we already know M, f, and L. And indirectly we already know λ too. On a string fixed at its extremes we have standing waves ant the equation of the wavelength in function the number of the harmonic N_{harmonic} is:

\lambda_{harmonic}=\frac{2l}{N_{harmonic}}

It's is important to note that in our case L the length of the string is different from l the distance between the pin and fret to produce a Concert A, so for the first harmonic:

\lambda_{1}=\frac{2(0.425m)}{1}=0.85 m

We can now find T on (3) using all the values we have:

T= \frac{2.42\times10^{-3}(0.85* 440)^2}{0.45}

T=75.22 N

3 0
3 years ago
A 5 kg ball is sitting on top of a hill. It has a Potential Energy of 6000J. What is the height of the ball?​
natali 33 [55]

Explanation:

mass=5 kg

potential energy=6000j

height=?

Now

potential energy =m.g.h

or 6000=5*9.8*h

or 6000=49h

or 6000÷49=h

or h= 122.45m

6 0
3 years ago
TWO QUESTIONS!
solong [7]

The correct answer to the question is : 1) Converting energy and 2) Within about twenty years, natural gas forms.

EXPLANATION:

In coal fired power plants, the water is heated by burning coals. The heat produced in this process will convert water into steam. The steam is allowed to rotate the turbine. The turbine is attached to a generator which converts the kinetic energy of the steam into electric energy due to electromagnetic induction.

Hence, turbine helps in converting energy.

As per the second question, Walt listed the steps that occur during the formation of natural gas.

The natural gas is produced due to natural phenomenon. For this, millions of years are passed. So, it is a long range process in which the fossil of animals and planets buried beneath the surface are converted into natural gas under high pressure.

Hence, the mistake of Walt is  that the natural gas is produced withing twenty years.

7 0
3 years ago
Read 2 more answers
A magnifying glass uses a convex lens of focal length 6.25 cm. When it is held 5.20 cm in front of an object, what is the image
mars1129 [50]

Answer:

The answer is either 5 or I'm learning something different and I just can't read

Explanation:

I hope this helped...

7 0
3 years ago
A bare helium nucleus has two positive charges and a mass of 6.64×10−27kg(a) Calculate its kinetic energy in joules at 2.00% of
grandymaker [24]

To solve this problem we will apply the concepts related to kinetic energy and energy conservation. The kinetic energy will be expressed in terms of mass and speed, as well as load and voltage. From this last expression we will find the charges by electron and by Helium nucleus.

a ) Kinetic Energy is given as

KE = \frac{1}{2} mv^2

Replacing with our values we have that

KE = \frac{1}{2} (6.64*10^{-27})(2.0\% (3.00*10^8))^2

KE = 1.1935*10^{-13}J

Therefore the kinetic energy of the helium nucleus is 1.1935*10^{-13}J

PART B) Now for calculate the electron volts we use the kinetic energy as a expression between the charge and the voltage, that is

KE = qV

Here,

q = Charge of an electron

V = Voltage

Rearranging to find the potential we have,

V = \frac{KE}{q}

V = \frac{1.19*10^{-13}}{1.6*10^{-19}}

V = 743750eV

Therefore the kinetic energy in electron vols is 743750eV

PART C) Applying the same relationship but now using the Helium core load, we will have to

KE = QV

Here,

Q = Charge of a helium nucleus

V = Voltage

Rearranging to find the potential we have

V = \frac{KE}{Q}

But we need to note that the charge is equal to the number of charge for the unit charge, then

Q = \text{No. Charge} \times \text{Unit Charge}

Q = (2)(1.6*10^{-19}C)

Q = 3.2*10^{-19}C

Now replacing we have that

V= \frac{1.19*10^{-13}}{32*10^{-19}}

V = 371875V

Therefore the voltage applied is  371875V

5 0
3 years ago
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