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zepelin [54]
3 years ago
9

You drop some ice and notice a piece appears to slide across the kitchen floor without slowing down (until it hits the wall). wh

at kept the ice moving at a fairly constant speed?
a. force
b. inertia
c. momentum
d. kinetic energy
Physics
2 answers:
SVETLANKA909090 [29]3 years ago
8 0
D.inertia ....................
Grace [21]3 years ago
7 0
D.Inertia<span> kept the ice moving at a fairly constant speed.</span>
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Answer:

B. Mechanical energy= 50J+30J=80J

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Laws of motion are important for the study of objects that are not in motion and objects in motion. Is it true or false?
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Gotta be true because physics
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Read 2 more answers
What is the volume of the cone?
dezoksy [38]

Answer:

42.417 cm³

Explanation:

The formula to find the volume of a cone is :

V = \frac{1}{3} × π r² h

Here,

r ⇒ radius ⇒ 3 cm

h ⇒ height ⇒ 4.5 cm

<u>Let us find it now.</u>

V = \frac{1}{3} × π r² h

V = \frac{1}{3} × π × 3 × 3 × 4.5

V = \frac{1}{3} × π × 9 × 4.5

V = \frac{1}{3} × π × 9 × 4.5

V = \frac{1}{3} × π × 40.5

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V = \frac{1}{3} × 127.251

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4 0
2 years ago
At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to 1515
Talja [164]

Complete  Question

At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to 1/5.

Answer:

The  angle is  

Explanation:

From the question we are told that

   The light emerging from second Polaroid is 1/5 the  unpolarized

Generally the intensity of light emerging from the first Polaroid is mathematically represented as

             I_1 = \frac{I_o}{ 2 }

Generally from the Malus law the intensity of light emerging from the second Polaroid  is mathematically represented

      I_2  =  I_1 cos^2 (\theta )

=>   cos^2 (\theta ) =  \frac{I_2}{I_1 }

=>   cos (\theta) =  \sqrt{ \frac{I_2}{I_1} }

From the question I_2  =  \frac{I_o}{5}

     cos (\theta) =  \sqrt{ \frac{ \frac{ I_o}{5} }{\frac{I_o}{2} } }

     cos (\theta) =  \sqrt{ \frac{2}{5} }

=>    \theta =   cos ^{-1} [\sqrt{\frac{2}{5}}  ]

=>    \theta  =  50.77^o

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3 years ago
Help please in science
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The amplitude is 0.8 cm. The wavelength is 2.0 cm.
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