Answer:
Therefore the speed of q₂ is 1961.19 m/s when it is 0.200 m from from q₁.
Explanation:
Energy conservation law: In isolated system the amount of total energy remains constant.
The types of energy are
- Kinetic energy.
- Potential energy.
Kinetic energy 
Potential energy =
Here, q₁= +5.00×10⁻⁴C
q₂=-3.00×10⁻⁴C
d= distance = 4.00 m
V = velocity = 800 m/s
Total energy(E) =Kinetic energy+Potential energy
+ 

=(1280-337.5)J
=942.5 J
Total energy of a system remains constant.
Therefore,
E
+ 




m/s
Therefore the speed of q₂ is 1961.19 m/s when it is 0.200 m from from q₁.
The time taken for him to move the bin 6.5 m is 2.30 s.
The given parameters;
- <em>weight of the load, w = 557 N</em>
- <em>force applied , F = 410 N</em>
- <em>angle of force, = 15°</em>
- <em>coefficient of kinetic friction = 0.46</em>
- <em>distance moved, d = 6.5 m</em>
The net horizontal force on the recycling bin is calculated as follows;

where;
- <em>m is the mass of the recycling bin</em>
- <em />
<em> is the frictional force </em>
W = mg

The net horizontal force on the recycling bin is calculated as;

The time taken for him to move the bin 6.5 m is calculated as follows;

Thus, the time taken for him to move the bin 6.5 m is 2.30 s.
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Answer:
It is equal to the overall momentum before collision, so far no external object is involved.
Explanation:
Momentum is always conserved during collision as a rule. This is equal to the product of the mass and velocity. Thank you.
Answer:
B. There are no forces acting on the ball.
Explanation:
There are no forces acting on the ball.