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4 years ago

Why is dark silicon currently necessary?

Physics

1 answer:

ra1l [238]4 years ago

6 0

Answer:

Architects have initiated several efforts in leveraging the Dark Silicon to design application-specific and accelerator-rich architectures.Recently, researchers have explored how Dark Silicon exposes new challenges and opportunities for the EDA community. In particular, they have demonstrated the thermal, reliability (soft error and aging), and process variation concerns for Dark Silicon many-core processors.

- EDA is Electronic Design Automation -

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B. Add the potential and kinetic energy for each location to find the total energy. What do you notice

ExtremeBDS [4]

Answer: do

Explanation:

4 0

2 years ago

What is the wavelength of a soundwave moving at 340 m/s with a frequency of 265 Hz?

lyudmila [28]

Wave speed = frequency * wavelength
Rearrange so it's equal to wavelength. Do this by diving both sides by frequency to leave you with:
Wave speed / frequency = wavelength
340 / 265 = 1.2830 m

4 0

3 years ago

At some instant and location the electric field associated with an electromagnetic wave in vacuum has the strength 96.5 V/m. Fin

prisoha [69]

Answer:

B = 32.17 x 10^-8 Tesla

u = 8.24 x 10^-8 J/m^3

P/A = 24.72 W/m^2

Explanation:

E = 96.5 V/m

velocity of light, c = 3 x 10^8 m/s

Let B be the magnetic field.

The relation between the electric field strength and the magnetic field strength is given by

B = E / c = 96.5 / (3 x 10^8) = 32.17 x 10^-8 Tesla

Let u be the energy density.

$u = \frac{1}{2}\times \varepsilon _{0}E^{2}+\frac{1}{2\mu _{0}}B^{2}$

$u = \frac{1}{2}\times 8.854\times 10^{-12}\times 96.5\times 96.5+\frac{1}{2\times 4\times 3.14\times 10^{-7}}\times 32.17^{2}\times 10^{-16}$

u = 8.24 x 10^-8 J/m^3

Let Power flow per unit area is

P/A = u x c = 8.24 x 10^-8 x 3 x 10^8 = 24.72 W/m^2

7 0

3 years ago

A 481-m long spaceship passes by an observer at the speed of 2.70×10^8 m/s. What length does the observer measure for the spaces

galben [10]

Answer:

209.66 m

Explanation:

Given:

Original length of the spaceship, L = 481 m

Speed of the spaceship, v = 2.70 × 10⁸ m/s

Now,

using the concept of length contraction, we have

$L=\frac{L'}{\sqrt{1-\frac{v^2}{c^2}}}$

where,

L' is the observed length

c is the speed of the light

Thus,

on substituting the respective values, we get

$481=\frac{L'}{\sqrt{1-\frac{(2.70\times10^8)^2}{(3\times10^8)^2}}}$

L' = 209.66 m

3 0

4 years ago

What kind of image is formed by a plane mirror

lisov135 [29]

A distorted image. :3

hope i help

5 0

4 years ago