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4 years ago

Why is dark silicon currently necessary?

Physics

1 answer:

ra1l [238]4 years ago

6 0

Answer:

Architects have initiated several efforts in leveraging the Dark Silicon to design application-specific and accelerator-rich architectures.Recently, researchers have explored how Dark Silicon exposes new challenges and opportunities for the EDA community. In particular, they have demonstrated the thermal, reliability (soft error and aging), and process variation concerns for Dark Silicon many-core processors.

- EDA is Electronic Design Automation -

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The positive terminal of a voltage source (V=12V ) is connected to a capacitor C1 = 4 μF. This capacitor is then connected to a

gizmo_the_mogwai [7]

Answer: 16 μC

Explanation: In order to solve this problem we have to reduce to the equivalent capacitor for the initial conection:

see the attach field to details.

3 0

3 years ago

Calculate the ratio of the kinetic energy of an electron to that of a proton if their wavelengths are equal. Assume that the spe

goblinko [34]

Answer:

the ratio of the kinetic energy of an electron to that of a proton if their wavelengths are equal is 1835.16 .

Explanation:

We know, wavelength is expressed in terms of Kinetic Energy by :

$\lambda=\dfrac{h}{\sqrt{2mE}}$

Therefore , $E=\dfrac{h^2}{2 \lambda^2 m}$

It is given that both electron and proton have same wavelength.

Therefore,

$E_e=\dfrac{h^2}{2 \lambda^2 m_e}$ .... equation 1.

$E_p=\dfrac{h^2}{2 \lambda^2 m_p}$ .... equation 2.

Now, dividing equation 1 by 2 .

We get ,

$\dfrac{E_e}{E_p}=\dfrac{\dfrac{h^2}{2 \lambda^2 m_e}}{\dfrac{h^2}{2 \lambda^2 m_p}}\\\\\\\dfrac{E_e}{E_p}=\dfrac{m_p}{m_e}$

Putting value of mass of electron = $9.1\times 10^{-31}\ kg$ and mass of proton = $1.67\times 10^{-27}\ kg.$

We get :

$\dfrac{E_e}{E_p}=\dfrac{1.67\times 10^{-27}\ kg}{9.1\times 10^{-31}\ kg}=1835.16$

Hence , this is the required solution.

4 0

4 years ago

Read 2 more answers

Identifying the factors contributing to and acting as determinant factors of health disparities during the program theory and de

Sav [38]

Answer:

a) True

Explanation:

A program-specific message provided to an individual or group with the intention of raising awareness of a health condition, motivating behavior change, removing perceived barriers to participating in a health habit, or something else relating to the program's aims and objectives. The most effective intervention messages are usually theory-based and culturally adapted.

5 0

3 years ago

A gymnast jumps directly up onto a beam that is 1.5 m high. From the beam, she jumps 0.5 m straight up and lands back on the bea

tatiyna

Answer:

D. 2.5 m

Explanation:

1.5 m up to the beam + 0.5 m up + 0.5 m down = 2.5 m total

5 0

4 years ago

Did you think about this over Christmas? I did (-: Before Christmas a 65kg student consumes 2500 Cal each day and stays at the s

Gnesinka [82]

Answer:

a) Em = 332.8 J , b) # jump = 13, c) It is reasonable since there are not too many jumps , d) lower the calories consumed

Explanation:

a) Let's use energy conservation

Initial. On the floor

Em₀ = K = ½ m v²

Final. The highest point

Emf = U = m g h

Energy is conserved

Em₀ = Emf

½ m v² = m g h

h = ½ v² / g

h = ½ 3.2² /9.8

h = 0.52 m

b) When he was at home he maintained his weight with 2500 cal / day. In his parents' house he consumes 3500 cal / day, the excess of calories is

Q = 3500 -2500 = 1000cal / day

Let's reduce this value to the SI system

Q = 1000 cal (4,184 J / 1 cal) = 4186 J / day

Now the energy in each jump is

Em = K = ½ m v²

Em = ½ 65 3.2²

Em = 332.8 J

They indicate that the body can only use 25% of this energy

Em effec = 0.25 332.8 J

Em effec = 83.2 J

This is the energy that burns the body

Let's use a Proportion Rule (rule of three), if a jump spends 83.2J how much jump it needs to spend 1046 J

# jump = 1046 J (1 jump / 83.2 J)

# jump = 12.6 jumps / day

# jump = 13

c) It is reasonable since there are not too many jumps

d) That some days consume more vegetables to lower the calories consumed

7 0

4 years ago