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3 years ago

Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the

Physics

1 answer:

Andreyy893 years ago

3 0

I would say 5.6 to the 4 and I’ll I did was add it to both side

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Trivia Time!! At what velocity does light move?

Maslowich

Explanation:

Light Light from a moving source travels at 300,000 km/sec (186,000 miles/sec).

Note:

The Speed of Light Is Constant.

7 0

2 years ago

Read 2 more answers

How does changes in distance affect the gravitational pull between two objects? Describe and give one example.

maxonik [38]

The formula is

F_grav = G * m1 * m2 / r^2

G m1 and m2 are going to stay the same once chosen no matter what the distance is. The only thing that will change is the distance.

As the distance increases, the Gravitational Force will decrease. It will decrease by quite a bit.

As the distance decreases, the gravitational force will Increase.

The relationship is inverse. The moon travelling around the earth is one example. The earth travelling around the sun is another.

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4 years ago

A=vf-vi/t is the equation for calculating the acceleration of an object. write out the relationship shown in the equation using

Lelechka [254]

Basically it is the difference in velocity divided by the time it takes to make that change.

3 0

3 years ago

Help 100 points will give brainleyest

Airida [17]

Answer:

Explanation:

The sound waves are compromised. It decrompesses each time which makes the sound gets lower and lower.

7 0

3 years ago

A flat, 181 ‑turn, current‑carrying loop is immersed in a uniform magnetic field. The area of the loop is 4.97 cm2 and the angle

Sidana [21]

Answer:

B = 0.135T

Explanation:

To find the magnitude of the magnetic field you use the following formula, for the torque produced by a magnetic field B in a loop:

$\tau=NIABsin\theta$ (1)

τ: torque = 1.51*10^-5 Nm

I: current = 2.47mA = 2.47*10^-3 A

B: magnitude of the magnetic field

A: area of the loop = 4.97cm^2 = 4.97(10^-2m)^2=4.97*10^-4m^2

N: turns = 181

θ: angle between B and the magnetic dipole (same as the direction of the normal to the plane)

You replace the values of the parameters in (1). Furthermore you do B the subject of the formula:

$B=\frac{\tau}{NIAsin\tetha}=\frac{1.51*10^{-5}Nm}{(181)(2.47*10^{-3}A)(4.97*10^{-4}m^2)(sin30.1\°)}=0.135T$

3 0

3 years ago