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ZanzabumX [31]
3 years ago
12

A 500 kg roller coaster moving at 15 m/s suddenly comes to a stop at the end of the ride. How much work energy was needed to sto

p the coaster?
Physics
1 answer:
saveliy_v [14]3 years ago
4 0

Answer:

energy required=-energy lost

energy lost=change in kinetic energy

EL=1/2 mv^2

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What’s the answer?hhhu
allsm [11]

Which one if you want independent variable meaning that means  variable (often denoted by x ) whose variation does not depend on that of another.

7 0
3 years ago
Mr. Ben drove from Town A to Town B. For the first 3 h, he traveled at an average speed of
Vanyuwa [196]

Answer:

It’s 7 hours

Explanation:

You have to use the formula your teacher has given to you plug in the numbers then solve be sure to use a calculator made for physics it helps a lot :)

8 0
3 years ago
The formula is x = 1/2 at^2 and I have managed to fill in the variables as this. d = 1/2 9.81 m/s^2 1^2
Artyom0805 [142]

Right, as you mentioned in the comments, you find d by plugging in the different values of t.

For t=1\,\mathrm s, we have

d=\dfrac12\left(9.81\,\dfrac{\mathrm m}{\mathrm s^2}\right)(1\,\mathrm s)^2

d=\left(4.905\,\dfrac{\mathrm m}{\mathrm s^2}\right)\left(1\,\mathrm s^2\right)

d=4.905\,\mathrm m

Similarly, for t=2\,\mathrm s, you get

d=\dfrac12\left(9.81\,\dfrac{\mathrm m}{\mathrm s^2}\right)\left(2\,\mathrm s\right)

d=\left(4.905\,\dfrac{\mathrm m}{\mathrm s^2}\right)\left(4\,\mathrm s^2\right)

d=19.62\,\mathrm m

8 0
3 years ago
A suspension bridge has twin towers that are 1300 feet apart. Each tower extends 180 feet above the road surface. The cables are
zhannawk [14.2K]

Answer:

y = 17.04 ft

Explanation:

Since the cable touches the road at the mid point of two towers

so here we have vertex at that mid point taken to be origin

now the maximum height on the either side is given as

y = 180 ft

horizontal distance of the tower from mid point is given as

x = \frac{1300}{2} = 650 ft

now from the equation of parabola we have

y = k x^2

180 = k(650^2)

k = 4.26 \times 10^{-4}

now we have

y = (4.26 \times 10^{-4})x^2

now we need to find the height at distance of 200 ft from center

so we have

y = (4.26 \times 10^{-4})(200^2)

y = 17.04 ft

8 0
3 years ago
What is another word for cycles per second??
Hatshy [7]
Frequensey or hertz, I looked this up on the internet!
5 0
3 years ago
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