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fredd [130]
3 years ago
9

In each of two coils the rate of change of the magnetic flux in a single loop is the same. The emf induced in coil 1, which has

159 loops, is 2.78 V. The emf induced in coil 2 is 4.11 V. How many loops does coil 2 have
Physics
2 answers:
wel3 years ago
7 0

Answer:

250 loops

Explanation:

We know that induced emf, E = -NdФ/dt wnere N = number of turns and dФ/dt = rate of change of magnetic flux.

Let E₁, E₂ and N₁, N₂ be the emfs and number of turns of coils 1 and 2 respectively. Since dФ/dt is the same for both coils,

E₁ = -N₁dФ/dt  (1) and E₂ = -N₂dФ/dt (2)

Dividing (1) by (2), we have

E₁/E₂ = -N₁dФ/dt/-N₂dФ/dt = N₁/N₂

E₁/E₂ = N₁/N₂

N₂ = (E₂/E₁)N₁

Given that E = 2.78 V, N₁ = 159 loops and E₂ = 4.11 V,  

N₂ = (E₂/E₁)N₁ = (4.11/2.78)159 = 250 loops

irinina [24]3 years ago
4 0

Answer:

 Coil 2 have  235  loops

Explanation:

Given  

The number of loops in coil 1 is n ₁= 159

The emf induced in coil 1 is  ε ₁ = 2.78 V

The emf induced in coil 2 is  ε ₂ = 4.11 V

Let

n ₂  is the number of loops in coil 2.

Given, the emf in a single loop in two coils are same. That is,

ϕ ₁/n ₁= ϕ ₂ n ₂⟹ 2.78/159 = 4.11/ n ₂

n₂=\frac{159 * 4.11}{2.78}

n₂=235

Therefore, the coil 2 has  n ₂= 235  loops.

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nadya68 [22]

Answer:

the magnitude of first force = 3 × 5= 15 N

ANd, the magnitude of second force = 5 × 5 = 25 N

Explanation:

The computation of the magnitude of the each force is shown below:

Provided that

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Based on the above information

Resultant force i.e. F = √ F_1^2 +F_2^2 + 2 F_1F_2cos\theta

35 = √[(3x)²+ (5x)²+ 2 (3x)(5x) cos 60°]

 35 =√ 9x² + 25x² + 15x²    (cos 60° = 0.5)

35 = √49 x²

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So, the magnitude of first force = 3 × 5= 15 N

ANd, the magnitude of second force = 5 × 5 = 25 N

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Answer:

The angle through which the wheel turned is 947.7 rad.

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The angle through which the wheel turned can be calculated by applying the following kinematic equation;

\omega_f^2 = \omega_i^2 + 2\alpha \theta\\\\\theta = \frac{\omega_f^2\   -\  \omega_i^2}{2\alpha } \\\\\theta = \frac{(72)^2\   -\  (33.3)^2}{2(2.15)}\\\\\theta = 947.7 \ rad

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