Sounds waves travel fastest through solids
Answer:
6.2 ohm
Explanation:
Let R1 = 5 ohm
R2= 3 ohm
R3= 2 ohm
Since R3 and R2 are parallel then net resistance R' is given by
1/R' = 1/R2 + 1/R3
1/R' = 1/3 + 1/2
1/R' = 5/6
then
R' = 6/5 = 1.2 ohm
Now R1 and R' are in series, so
R = R1 + R'
R = 5 + 1.2
R = 6.2 ohm
I'm pulling this from the top of my head but I'm going to guess:
A.) formed for the first blank and cooled for the second blank. I hope this helped.
Answer:
it will take 36.12 ms to reduce the capacitor's charge to 10 μC
Explanation:
Qi= C×V
then:
Vi = Q/C = 30μ/20μ = 1.5 volts
and:
Vf = Q/C = 10μ/20μ = 0.5 volts
then:
v = v₀e^(–t/τ)
v₀ is the initial voltage on the cap
v is the voltage after time t
R is resistance in ohms,
C is capacitance in farads
t is time in seconds
RC = τ = time constant
τ = 20µ x 1.5k = 30 ms
v = v₀e^(t/τ)
0.5 = 1.5e^(t/30ms)
e^(t/30ms) = 10/3
t/30ms = 1.20397
t = (30ms)(1.20397) = 36.12 ms
Therefore, it will take 36.12 ms to reduce the capacitor's charge to 10 μC.
Answer:
The number of turns in the solenoid is 1.95 x 10⁴.
Explanation:
given information:
the length of solenoid, L = 0.34 m
magnetic field, B = 6.5 T
current, I = 90 A
to find the number of turn in solenoid, we can start from the magnetic field equation,
B = μ₀nI, n = N/L
B = magnetic field (T)
μ₀ = permeability (4π × 10⁻⁷ T.m/A)
n = the number turn per unit length (turn/m)
I = current (A)
N = the number turn in solenoid
L = the length of solenoid
thus,
B = μ₀IN/L
N = B L/μ₀I
= (6.5) (0.34)/(4π × 10⁻⁷) (90)
= 1.95 x 10⁴ turn
