Answer:
T=270 K
Explanation:
Power absorbed by the Moon
the reason for choosing the area as π R^2 and not 4π R^2 is because the absorbed light is only from the surface facing the Sun which is a disc.
Using Stefan Boltzmann's law,
So, using Conservation of Energy,
this gives, T = 270 K. This is the temperature of the sunlight side of the Moon.
Anaphase, the shortest stage of mitosis
From gas to liquid
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Answer:
ΔE = GMm/24R
Explanation:
centripetal acceleration a = V^2 / R = 2T/mr
T= kinetic energy
m= mass of satellite, r= radius of earth
= gravitational acceleration = GM / r^2
Now, solving for the kinetic energy:
T = GMm / 2r = -1/2 U,
where U is the potential energy
So the total energy is:
E = T+U = -GMm / 2r
Now we want to find the energy difference as r goes from one orbital radius to another:
ΔE = GMm/2 (1/R_1 - 1/R_2)
So in this case, R_1 is 3R (planet's radius + orbital altitude) and R_2 is 4R
ΔE = GMm/2R (1/3 - 1/4)
ΔE = GMm/24R