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NARA [144]
3 years ago
5

If a girl does 1,350 Joules of work to pedal her bike using a force of 75 N, how far did she ride her bike?

Physics
1 answer:
shepuryov [24]3 years ago
7 0

Answer:

D = 18m

Explanation:

We use this formula:

Work = Force * Distance

Now, we replace it:

W = F*D

1,350J = 75N * D

D = 1,350/75

D = 18m

Hope it was helpful ;)

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5 0
3 years ago
A force does work on an object if a component of the force is
IrinaK [193]

Answer:

A force does work on an object if a component of the force is parallel to the displacement of the object.

Explanation:

Work, a measurement of energy is said to be done when a force applied to an object results in the movement of that object to a certain distance and direction. Force is the act of push or pulls occurs on an object as a result of the interaction between that object with another one and displacement is the distance and direction covered by that object as a result of the force applied on it.

The work done (W) by a constant force (F) is equal to the product of the force in the direction of displacement of the object and the distance (d) moved by the object i.e., W = F * d.

The angle between the displacement and the force is θ, then the work done, W = Fd cos θ  ........ (1)

Positive work - Force acts in the same direction with respect to the displacement of the object. Here, θ is zero, so cos θ i.e., cos 0 is 1. Therefore, from the equation (1), W = Fd (i.e., work done by the force is positive).

Negative work - Force acts in the opposite direction with respect to the displacement of the object.  Here, θ is 180°, so cos θ i.e., cos 180° is -1. Therefore, from the equation (1), W = -Fd (i.e., work done by the force is negative).

If a force is applied to an object and it does not move, then the work done is zero i.e., W = F * 0 = 0. Also, if the force and displacement are at right angle to each other, then θ is 90°. Therefore, from the equation (1), W = 0 since cos 90° is zero.

7 0
4 years ago
If a 50microAmps current is flowing then how many electrons pass a point each minute to 2 sig figs? Please add an explanation as
defon
The equation you need to use is Q=IT where Q is the charge in C, I is the current in Amps and T is the time in seconds.

So we have T = 60s
I = 50 \times 10^-^6A
let's work out Q
Q=IT = (50\times 10^{-6}) \times 60 = 3 \times 10^-^3C
this is the total charge passing a point in a minute so divide by the charge of one electron (1.6 \times 10^{-19}) to find the number of electrons passing the point in a minute which equals 1.875 \times 10^{16}
6 0
3 years ago
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