Question

13.0 mL of hydrochloric acid (HCl) required to neutralize 36.11 ml of 0.045 M sodium hydroxide (NaOH). What is the molarity of hydrochloric acid?

Answer 1

Answer:

Molarity of HCl  = 0.12 M

Explanation:

Given data:

Volume of HCl = 13.0 mL

Volume of NaOH = 36.11 mL

Molarity of NaOH = 0.045 M

Molarity of HCl = ?

Solution:

Formula:

M₁V₁   =   M₂V₂

M₁= Molarity of HCl

V₁ =  Volume of HCl

M₂ = Molarity of NaOH

V₂ = Volume of NaOH

M₁ × 13.0 mL =  0.045 M ×  36.11 mL

M₁  = 1.62 M.mL /  13.0 mL

M₁  =0.12 M