Answer:
Distance, d = 0.049 meters
Explanation:
It is given that,
Mass of the pile, m = 2500 kg
It is dropped through a height of 8.0 m on each stroke, h = 8 m
The resisting force of the ground, ![F=4\times 10^6\ N](https://tex.z-dn.net/?f=F%3D4%5Ctimes%2010%5E6%5C%20N)
The work done in each stroke is equal to the potential energy of the pile driver such that,
![W=mgh](https://tex.z-dn.net/?f=W%3Dmgh)
Work done due to resistive force is :
![W=Fd](https://tex.z-dn.net/?f=W%3DFd)
So,
![Fd=mgh](https://tex.z-dn.net/?f=Fd%3Dmgh)
d is the distance covered by the post driven in on each stroke.
d = 0.049 meters
So, on each stroke the post driven is 0.049 meters far. Hence, this is the required solution.
Answer:
0.65 kg*m/s and 0.165 kg*m/s
Explanation:
Step one:
given data
mass m= 0.5kg
initial velolcity u=1.3m/s
final velocity v= 0.97m/s
Required
The change in momentum
Step two:
We know that the expression for impulse is given as
Ft= mv
Ft= 0.5*1.3
Ft= 0.65 kg*m/s
The expression for the change in momentum is given as
P= mΔv
substitute
Pt= 0.5*(1.3-0.97)
Pt= 0.5*0.33
Pt=0.165 kg*m/s
You need an additional point of data here: the enthalpy of fusion, or conversely the enthalpy of melting (they differ only by their sign). For water (or ice) that value is gotten from sources such as the internet
<span>ΔH°(fus) = 6.01 kJ/mole </span>
<span>Since you have 35 000g, how many moles do you have? </span>
<span>Moles H2O = 35000 g/(18.015 g/mole) = 1942.8 moles</span>
<span>So, take that ΔH°(fus) in kJ/mole, multiply by the number of moles, and there ya go!
</span>
6.01 x 1942.8 = 11,676 kJ of energy is released
Hope I helped!! xx
Exothermic reactions release energy.
True