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3 years ago

When the temperature of air rises, the amount of water needed for saturation

Physics

2 answers:

Oliga [24]3 years ago

7 0

It Increases. I just took a quiz with the same question.

Lemur [1.5K]3 years ago

6 0

<span>When the temperature of air rises, the amount of water needed for saturation increases. </span>

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A child bounces a 52 g superball on the sidewalk. The velocity change of the superball is from 20 m/s downward to 14 m/s upward.

marusya05 [52]

Answer:

Force on superball will be $=9.8222\times 10^{-4}N$

Explanation:

We have given mass of superball m = 52 gram = 0.052 kg

Velocity change from 20 m/sec downward to 14 m/sec upward

Let downward velocity is positive then upward velocity is negative

So downward velocity is + 20 m/sec and upward velocity is -14 m/sec

Time is given as 1800 sec

We know that acceleration is rate of change of velocity

So $a=\frac{20-(-14)}{1800}=0.0188m/sec^2$

According to newton second law

Force = ma = 0.052×0.0188 $=9.8222\times 10^{-4}N$

6 0

3 years ago

Read 2 more answers

The electric field in a region is uniform (constant in space) and given by E-( 148.0 1 -110.03)N/C. An additional charge 10.4 nC

enyata [817]

Answer:

The y-component of the electric force on this charge is $F_y = -1.144\times 10^{-6}\ N.$

Explanation:

<u>Given:</u>

Electric field in the region, $\vec E = (148.0\ \hat i-110.0\ \hat j)\ N/C.$
Charge placed into the region, $q = 10.4\ nC = 10.4\times 10^{-9}\ C.$

where, $\hat i,\ \hat j$ are the unit vectors along the positive x and y axes respectively.

The electric field at a point is defined as the electrostatic force experienced per unit positive test charge, placed at that point, such that,

$\vec E = \dfrac{\vec F}{q}\\\therefore \vec F = q\vec E\\=(10.4\times 10^{-9})\times (148.0\ \hat i-110.0\ \hat j)\\=(1.539\times 10^{-6}\ \hat i-1.144\times 10^{-6}\ \hat j)\ N.$

Thus, the y-component of the electric force on this charge is $F_y = -1.144\times 10^{-6}\ N.$

3 0

2 years ago

Help me on question 5

Sveta_85 [38]

I believe it is acceleration!

6 0

3 years ago

Read 2 more answers

What is the kinetic energy of a bike with a mass of 24 kg traveling at 3 m/s?

erastovalidia [21]

Answer:

KE = 1/2mv^2

KE = 1/2(24)(3^2)

KE = 12(9)

KE = 108 J

Let me know if this helps!

5 0

3 years ago

Consider the system consisting of two blocks connected by a rope and a pulley. The coefficient of static friction between the ra

RSB [31]

Answer:

1.2 kg

Explanation:

Let UP ramp be the positive direction

F = ma

T - Wt || - Ff = m(0)

mg - Μgsinθ - μΜgcosθ = 0

m(9.8) - 13sin35 - 0.36(13)cos35 = 0

m = 13(sin35 + 0.36cos35) / 9.8

m = 1.15205... ≈ 1.2 kg

5 0

2 years ago