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mihalych1998 [28]
2 years ago
6

Based on the equation below, how many moles of aluminum sulfate (Al2(SO4)3) will be produced from the reaction of 5.8 moles of a

luminum hydroxide (Al(OH)3) and excess sulfuric acid (H2SO4)?
Chemistry
1 answer:
andrey2020 [161]2 years ago
6 0
Answer:
2.9
Explanation:
1- we can see that for every 2 moles of aluminum hydroxide 1 mole of aluminum sulfate is made so we can make a relation

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The deprotonated organic acid (RCO2-) and protonated organic base (RNH3+) go into the aqueous layer because Organic compounds that are neither acids or bases do not react with either NaOH or HCl and, therefore remain more soluble in the organic solvent and are not extracted.

Explanation:

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What was the purpose of letting the transformed cells sit in LB for a few minutes before spreading them onto the plates?
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A 25.00 mL sample of vinegar was titrated with 39.27 mL of 0.4293 M NaOH. Calculate the concentration of acetic acid in the vine
QveST [7]

Answer:

0.6743 M

Explanation:

HC₂H₃O₂ + NaOH → NaC₂H₃O₂ + H₂O

First we <u>calculate how many NaOH moles reacted</u>, using the <em>definition of molarity</em>:

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<em>One NaOH moles reacts with one acetic acid mole</em>, so <u>the vinegar sample contains 16.86 mmoles of acetic acid as well</u>.

Finally we <u>calculate the concentration (molarity) of acetic acid</u>:

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