The correct answer is the Tyndall effect. This is also known as the Tyndall scattering. It is the light scattering by the particles in a colloid or in a suspension. This phenomenon is used to determine size and density of particles in colloidal matter.
Hello!
To determine [H₃O⁺], we need to apply the Henderson-Hasselback equation, since this is a case of an acid and its conjugate base:
![pH=pKa+log( \frac{[A^{-}] }{[HA]} )](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%20%7D%7B%5BHA%5D%7D%20%29)
Now, we use the definition of pH and clear [H₃O⁺] from there:
![pH=-log[H_3O^{+}]](https://tex.z-dn.net/?f=pH%3D-log%5BH_3O%5E%7B%2B%7D%5D%20)
![[H_3O^{+}] = 10^{-pH} =10^{-3,84}=0,00014 M](https://tex.z-dn.net/?f=%20%5BH_3O%5E%7B%2B%7D%5D%20%3D%2010%5E%7B-pH%7D%20%3D10%5E%7B-3%2C84%7D%3D0%2C00014%20M)
So, the [H₃O⁺] concentration is
0,00014 M
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Answer:
1.46g of PbCrO₄ are the theoretical yield
Explanation:
Theoretical yield is defined as the maximum amount of products that could be produced (Assuming a yield of 100%).
The reaction of Lead (II) nitrate with sodium chromate is:
Pb(NO₃)₂(aq) + Na₂CrO₄(aq) → PbCrO₄(s) + 2NaNO₃ (aq)
First, we need to find molar mass of each reactant in order to determine limiting reactant (As the reaction is 1:1, the reactant with the lower number of moles is the limiting reactant). The moles of the limiting reactant = moles of Lead (II) chromate (The precipitate):
<em>Moles Pb(NO₃)₂ -Molar mass: 331.21g/mol-</em>
1.50g * (1mol / 331.21g) = 4.53x10⁻³ moles Pb(NO₃)₂
<em>Moles Na₂CrO₄ -Molar mass: 161.98g/mol-</em>
1.75g * (1mol / 161.98g) = 0.0108 moles
Pb(NO₃)₂ is limiting reactant and moles of PbCrO₄ are 4.53x10⁻³ moles. The mass is:
4.53x10⁻³ moles PbCrO₄ * (323.19g / mol) =
<h3>1.46g of PbCrO₄ are the theoretical yield</h3>
Taste and colour of water is different in both pot and plastic bowl.
<h3>Comparison between water in pot and plastic bowl</h3>
The appearance of the water in the pot is different from that of the water in the plastic bowl because of the colour. We know that water adopt the colour of the container in which it has been kept.
The taste of water in the pot is somewhat sweeter and colder than water present in the pot due to presence of pores and composition of pot so we can conclude that taste and colour of water is different in both pot and plastic bowl.
Learn more about bowl here: brainly.com/question/1135250
