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melisa1 [442]
1 year ago
7

You are going to mix a 1:10 bleach solution with water to make 500 mL of a 1:35 bleach solution. How much 1:10 bleach solution s

hould you use?
(using the C1V1=C2V2 formula)
Chemistry
1 answer:
Nimfa-mama [501]1 year ago
6 0

The volume of the bleach solution for 1:10 that should be used is 1,750 mL.

<h3>Volume of bleach solution required</h3>

The volume of bleach solution required is calculated using concentration formula as follows;

C1V1 = C2V2

where;

  • C1 is initial concentration of the bleach solution
  • V1 is the initial volume of the bleach solution
  • C2 is the final concentration of the bleach solution
  • V2 is the final volume of the bleach solution

Make the initial volume of the bleach solution the subject of the formula as shown below;

V1 = C2V2/C1

Substitute the given parameters and solve for the initial volume of the bleach solution.

V1 = (35 x 500)/(10)

V1 = 1,750 mL

Thus, the volume of the bleach solution for 1:10 that should be used is 1,750 mL.

Learn more about concentration here: brainly.com/question/17206790

#SPJ1

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A 0.035 M solution of ephedrine has a pH of 11.33.

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b) Calculate <span>Kb</span> for ephedrine.

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White vinegar is a 5.0% by mass solution of acetic acid in water. If the density of white
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The pH = 2.41

<h3>Further explanation</h3>

Given

5.0% by mass solution of acetic acid

the density of white  vinegar is 1.007 g/cm3

Required

pH

Solution

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\tt M=\dfrac{\%mass\times \rho\times 10}{MW~acetic~acid}\\\\M=\dfrac{5\times 1.007\times 10}{60}\\\\M=0.839

Ka for acetic acid = 1.8 x 10⁻⁵

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