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3 years ago

Describe in your words what it means for a chemical reaction system to be at equilibrium.

1 answer:

6 0

To be at equilibrium means the rate of the forward reaction must equal the rate of the reverse reaction. This does not mean that there should be an equal amount of both products and reactants when at equilibrium. It simply means the RATES of the forward and the reverse are equal to one another.

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Part A Name the complex ion [Fe(CN)6]^3- . The oxidation number of iron is +3. Part B Name the complex ion [Cu(NH3)2(H2O)4]^2+ .

zvonat [6]

Answer:

Part A: Hexacyanoferrate (III)

Part B: DiammintetraaquoCupperate (II)

Part C: Dichlorobis(ethylenediamine) Chromate (II)

Part D: Triaquocarbonylnickel (II) Sulphate

Part E: Potassium Dicarbonatedifluoroplatinate (II)

Explanation:

For naming the complex ions there is a specific rule

Nomenclature of the complex ions are as follow

write a correct formulae
Indicate the oxidation number of metal in the complex

The oxidation number should write in the roman numeral in perenthasis after metal name
Ligand named before the metal ion
Ligan can be named in following order

* 1st negative, 2nd neutral, 3rd positive

* If there are more than 2 same charged ligand the write in

alphabetical order.

Write prefix i.e di, tri, tetra for multiple monodentate ligands
Anions name end at ido the replace the final name.
Neutral ligands named as their usual name, but there are some exceptions such as

NH3 named as ammine

H2O names aqua or aquo

CO named ascarbonyl

NO named as nitrosyl

If the complex is an anion, then name of the central atom will end in -ate, and its Latin name will be used except for mercury
The name of full complex will end with cation or anion with separate word.

Keeping the rules in mind the complexes named as following.

_________________________

Part A:

[Fe(CN)₆]³⁻

Name of the Complex : Hexacyanoferrate (III)

___________________

Part B:

[Cu(NH₃)₂(H₂O)₄]²⁺

Name of the Complex : DiammintetraaquoCupperate (II)

_______________________

Part C

CrCl₂(en)₂

Name of the Complex : Dichlorobis(ethylenediamine) Chromate (II)

________________________

Part C

[Ni(H₂O)₃(CO)]SO₄

Name of the Complex : Tetraaquocarbonylnickel (II) Sulphate

______________________

Part E

K₄[Pt(CO₃)₂F₂]

Name of the Complex : Potassium Dicarbonatedifluoroplatinate (II)

5 0

2 years ago

Ok help it’s for homework

never [62]

Ability to moderate temperatures is not a property of water

4 0

2 years ago

Read 2 more answers

In a certain time, light travels 4.96 km in a vacuum. during the same time, light travels only 3.36 km in a liquid. what is the

Natali5045456 [20]

the refractive index of the liquid is 1.476

The refractive index, which has no dimensions, measures how quickly light passes through a substance.

It can also be described as the difference between the speed of light in a vacuum and a medium.

Refractive index is equal to the product of the light's liquid and vacuum speeds.

Therefore.

speed of light in vacuum = 4.96 km/t

speed of light in liquid = 3.36 km/t

Refractive index = 4.96/3.36

Refractive index =1.476

Therefore, the refractive index of the liquid is 1.476

To learn more about refractive index

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6 0

1 year ago

Convert 6.620 × 102 kg to units of mg.

Neko [114]

Answer:

675,240

Explanation:

3 0

3 years ago

Many enzymes are inhibited irreversibly by heavy metal ions such as Hg2+ , Cu2+ , or Ag+ , which can react with essential sulfhy

3241004551 [841]

Answer:

The minimum molecular weight of the enzyme is 29.82 g/mol

Explanation:

Step 1: Given data

The volume of the solution = 10 ml = 10*10^-3L

Molarity of the solution = 1.3 mg/ml

moles of AgNO3 added = 0.436 µmol = 0.436 * 10^-3 mmol

Step 2: Calculate the mass

Density = mass/ volume

1.3mg/mL = mass/ 10.0 mL

mass = 1.3mg/mL *10.0 mL = 13mg

Step 3: Calculate minimum molecular weight

Molecular weight = mass of the enzyme / number of moles

Molecular weight of the enzyme = 13mg/ 0.436 * 10^-3 mmol

Molecular weight = 29.82 g/mole

The minimum molecular weight of the enzyme is 29.82 g/mol

7 0

3 years ago