Answer:
We have 0.117 moles Mg^2+ and 0.234 moles Cl-
The number of Mg^2+ ions = 7.04 *10^22 ions
The number of Cl- ions = 1.4*10^23 ions
Explanation:
Step 1: Data given
Volume of magnesium chloride = 63.1 mL
Concentration of solution = 1.85 M
Step 2: Calculate moles MgCl2
Moles MgCl2 = concentration * volume
Moles MgCl2 = 1.85 M * 0.0631 L
Moles MgCl2 = 0.117 moles
Step 3: Calculate moles of ions
MgCl2 → Mg^2+ + 2Cl-
For 1 mol MgCl2 we have 1 mol Mg^2+ and 2 moles Cl-
For 0.117 moles MgCl2 we have 0.117 moles Mg^2+ and 2*0.117 = 0.234 moles Cl-
The number of Mg^2+ ions = 0.117 * 6.022 *10^23 = 7.04 *10^22 ions
The number of Cl- ions = 1.4*10^23 ions
