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netineya [11]
3 years ago
14

Zn(s) + HCl(aq) → ZnCl2(aq) + H2(g) ↑

Chemistry
1 answer:
WINSTONCH [101]3 years ago
6 0

Hey there!

Zn + HCl → ZnCl₂ + H₂

First, balance Cl.

1 on the left, 2 on the right. Add a coefficient of 2 in front of HCl.

Zn + 2HCl → ZnCl₂ + H₂

Next, balance H.

2 on the left, 2 on the right. Already balanced.

Lastly, balance Zn.

1 on the left, 1 on the right. Already balanced.

Our final balanced equation:

Zn + 2HCl → ZnCl₂ + H₂

Hope this helps!

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Explanation:

Given that:

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Also, let the constant rate for the catalyzed biochemical reaction = K₁

let the constant rate for the uncatalyzed biochemical reaction = K₂

If the  rate constant for the reaction increases by a factor of 3.50 × 10³ as compared with the uncatalyzed reaction, That implies that:

K₁ = 3.50 × 10³

K₂ = 1

Now, to calculate the activation energy for the catalyzed reaction going by the following above parameter;

we can use the formula for Arrhenius equation;

K=Ae^{\frac{-E}{RT}}

If K_1=Ae^{\frac{-E_1}{RT}} -------equation 1     &

K_2=Ae^{\frac{-E_2}{RT}} -------equation 2

\frac{K_1}{K_2} = e^{\frac{-E_1-E_2}{RT}

E_1= E_2-RT*In(\frac{K_1}{K_2})

E_1= 50,000-8.314*310.15*In(\frac{3.50*10^3}{1})

E_1 = 28957.39292  J/mol

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Answer : The concentration of H_3O^+ and OH^- are 7.94\times 10^{-5} and 1.258\times 10^{-10} respectively.

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