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MA_775_DIABLO [31]
3 years ago
5

Understanding coefficients

Chemistry
1 answer:
Alex Ar [27]3 years ago
3 0

Answer:

Mg-9

N-6

C-2

O-4

Ca-9

P-6

O-24

Explanation:

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Answer:GLACIERS  ARE MADE UP OF  FALLEN SNOW OVER MILLION YEARS, IN MOST OF POLAR REGIONS  IT TURNS TO ICE AND WILL FLOW DOWNWARDS AND OUTWARDS UNDER ITS OWN PRESSURE

AND THE LARGEST GLACIER IN THE WORLD IS 60 MILES WIDE AND AROUND  270 MILES LONG.

IT COVERS 10% OF EARTH'S TOTAL LAND

Explanation:

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How to identify polars&non polar.
lesantik [10]
If the difference in electronegativtiy for the atoms in a bond are greater than 0.4,we consider the bond polar, if the electronegativity is less than 0.4, we consider it non polar. if there are no polar bonds, the molecule is non polar.
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4 years ago
Why does liquid move like it does when heated in the middle?
Lapatulllka [165]

Answer:

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6 0
2 years ago
What is the mass of 1.33 moles of Ba3(PO4)2?
Serga [27]

Answer:

801 g

Explanation:

From the question given above, the following data were obtained:

Number of mole of Ba₃(PO₄)₂ = 1.33 moles

Mass of Ba₃(PO₄)₂ =?

Next, we shall determine the molar mass of Ba₃(PO₄)₂. This can be obtained as follow:

Molar mass of Ba₃(PO₄)₂ = (137.3×3) + 2[31 + (4×16)]

= 411.9 + 2[31 + 64]

= 411.9 + 2[95]

= 411.9 + 190

Molar mass of Ba₃(PO₄)₂ = 601.9 g/mol

Finally, we shall determine the mass of Ba₃(PO₄)₂. This can be obtained as follow:

Number of mole of Ba₃(PO₄)₂ = 1.33 moles

Molar mass of Ba₃(PO₄)₂ = 601.9 g/mol

Mass of Ba₃(PO₄)₂ =?

Mole = mass /Molar mass

1.33 = Mass of Ba₃(PO₄)₂ / 601.9

Cross multiply

Mass of Ba₃(PO₄)₂ = 1.33 × 601.9

Mass of Ba₃(PO₄)₂ = 801 g

8 0
3 years ago
In a titration experiment a student uses 1.4 m hbr solution and the indicator phenolphthalein to determine the concentration of
Likurg_2 [28]
The question is incomplete. Complete question is attached below:
...........................................................................................................................

Answer: 
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL

We know that, M1V1 = M2V2
                        (HBr)      (KOH)

Therefore, M2 = M1V1/V2
                        = 1.4 X 15.4/22.10
                        = 0.9756 M

Concentration of KOH is 0.9756 M.

3 0
3 years ago
Read 2 more answers
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