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guapka [62]
3 years ago
8

How many charges do copper(II) and Carbide have

Chemistry
1 answer:
MAVERICK [17]3 years ago
5 0

Answer:

Copper is 2+ and carbide is 2-

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Ksivusya [100]
The first and Third graph
6 0
3 years ago
Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m
koban [17]

Here is the full question:

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes? (Round your answer to three decimal places.

Answer:

0.046 %

Explanation:

The rate-in;

R_{in} = \frac{0.04}{100}*2000

R_{in} = 0.8

The rate-out

R_{out} = \frac{A}{6000}*2000

R_{out} = \frac{A}{3}

We can say that:

\frac{dA}{dt}= 0.8-\frac{A}{3}

where;

A(0)= 0.2% × 6000

A(0)= 0.002 × 6000

A(0)= 12

\frac{dA}{dt} +\frac{A}{3} =0.8

Integration of the above linear equation =

e^{\int\limits \frac {1}{3}dt } = e^{\frac{1}{3}t

so we have:

e^{\frac{1}{3}t}\frac{dA}{dt}} +\frac{1}{3}e^{\frac{1}{3}t}A = 0.8e^{\frac{1}{3}t

\frac{d}{dt}[e^{\frac{1}{3}t}A] = 0.8e^{\frac{1}{3}t

Ae^{\frac{1}{3}t} =2.4e\frac{1}{3}t +C

∴ A(t) = 2.4 +Ce^{-\frac{1}{3}t

Since A(0) = 12

Then;

12 =2.4 + Ce^{-\frac{1}{3}}(0)

C= 12-2.4

C =9.6

Hence;

A(t) = 2.4 +9.6e^{-\frac{t}{3}}

A(0) = 2.4 +9.6e^{-\frac{10}{3}}

A(t) = 2.74

∴ the concentration at 10 minutes is ;

=  \frac{2.74}{6000}*100%

= 0.0456667 %

= 0.046% to three decimal places

7 0
3 years ago
Which acid and base react in the formation of salt sodium chloride? hydrochloric acid and sodium hydroxide sodium carbonate and
malfutka [58]
Hydrochloric acid and sodium hydroxide

HCl + NaOh ----> NaCl + H2O
7 0
3 years ago
A 8L sample of gas at 250 K is cooled to 75 K. What is the volume of the gas after it is cooled?
Stells [14]

by \: Charles'\: law: \:  \\  \frac{v_{1}}{t_{1}}  =  \frac{v_{2}}{t_{2}}  \\

Where v is the volume(in L) and t is the temperature(in °K)

\frac{8}{250}  =  \frac{v_{2}}{75} \\\\4/5 =v_2/3 \\\\\boxed{v_{2} = \frac{12}{5}}\\\\\\\huge{=2.5 l}

7 0
2 years ago
Please solve quickly!!!
Maurinko [17]

Answer:

18 oxygen atoms

Explanation:

in order to from the 6 molecules carbon dioxide and 6 molecules of water you will have a total of 18 oxygen atoms

3 0
3 years ago
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