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scoray [572]
3 years ago
7

A girl walks 0.3 m/s. She moves 0.8 m/s 5 s later.

Physics
1 answer:
kompoz [17]3 years ago
7 0

Answer:

a = 0.1 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f}=v_{o}+a*t

Vf = final velocity = 0.8 [m/s]

Vo = initial velocity = 0.3 [m/s]

a = acceleration [m/s²]

t =  time = 5 [s]

0.8=0.3+a*t\\0.5 = 5*a\\a = 0.1 [m/s^{2}]

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You drag a suitcase of mass 8.2 kg with a force of f at an angle 41.9 ◦ with respect to the horizontal along a surface with kine
DedPeter [7]

Answer:

35.6 N

Explanation:

We can consider only the forces acting along the horizontal direction to solve the problem.

There are two forces acting along the horizontal direction:

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- The frictional force, whose magnitude is

F_f = \mu mg

where \mu=0.33, m=8.2 kg and g=9.8 m/s^2.

The two forces have opposite directions (because the frictional force is always opposite to the motion), and their resultant must be zero, because the suitcase is moving with constant velocity (which means acceleration equals zero, so according to Newton's second law: F=ma, the net force is zero). So we can write:

F_x - F_f=0\\F_x = F_f\\F cos \theta = \mu mg\\F=\frac{\mu mg}{cos \theta}=\frac{(0.33)(8.2 kg)(9.8 m/s^2)}{cos(41.9^{\circ})}=35.6 N

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A wheel of diameter 138 cm has an axle of diameter 9 cm. A force 120 N is exerted along the rim of the wheel. What force should
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Answer:

Explanation:

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