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____ [38]
3 years ago
11

Someone help me please

Mathematics
1 answer:
wolverine [178]3 years ago
7 0

Answer: Blue is longer

Step-by-step explanation: Blue islonger because it  strtches a

corss more than 3 it almost reaches 4 ( no it is 4 dots long )

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A=1/2•e•m <br> solve the following formula for e
Vedmedyk [2.9K]

(1 / 2) x e x meters =

1.35914091 meters

8 0
3 years ago
Whats the answer for 6b+7-2b=1+5b
Alecsey [184]

Solution,6b+7-2b=1+5b\quad :\quad b=6

Steps:

6b+7-2b=1+5b

\mathrm{Group\:like\:terms}, 6b-2b+7=1+5b

\mathrm{Add\:similar\:elements:}\:6b-2b=4b, 4b+7=1+5b

\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}, 4b+7-7=1+5b-7

\mathrm{Simplify}, 4b=5b-6

\mathrm{Subtract\:}5b\mathrm{\:from\:both\:sides}, 4b-5b=5b-6-5b

\mathrm{Simplify}, -b=-6

\mathrm{Divide\:both\:sides\:by\:}-1, \frac{-b}{-1}=\frac{-6}{-1}

\mathrm{Simplify}, b=6

\mathrm{The\:Correct\:Answer\:is\:b=6}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

3 0
3 years ago
Read 2 more answers
use the guide to construct a two column proof proving △aec≅△deb, given that ca is parallel to db and e is the midpoint of ad. gi
MrMuchimi

By using the AAA congruence property of Triangles, △aec≅△deb is proved

It is given two triangles, Δaec and Δdeb, where e is the common point known as the midpoint of ad

Also, it is given that,

ca ║db

We need to prove that, △aec≅△deb

Then we'll use AAA congruence property of Triangles to prove the situation

As ca ║db

then, ∠cae = ∠ebd  (Alternate angles)

∠ace = ∠edb (Alternate angles)

and ∠aec = ∠deb (common angles)

Thus, by AAA congruence property, △aec≅△deb

Hence, proved

To learn more about, congruence property, here

brainly.com/question/2039214

#SPJ4

5 0
1 year ago
Find the area to the nearest square foot of the shaded region below, consisting of a square with a circle cut out of it. Use 3.1
NeTakaya

Answer:

22 square feet

Step-by-step explanation:

Area of shaded region = Area of square - Area of circle. The diameter of the circle is also the length of the side of the square as the circumference of the circle is on the circumference of the square.

Area of circle = 3.14 × r × r

r = 10 ÷ 2

= 5

Area of circle = 3.14 × 5 × 5

= 78.5

Area of square = length × length

Area of square = 10 × 10

= 100

Area of shaded region = Square - Circle

= 100 - 78.5

= 21.5

= 22 (to the nearest square foot)

I hope this helps :)

7 0
3 years ago
The equation of a circle whose center is at ( 4,0 ) and radius is length 2 ( square root ) 3
Vesna [10]
The equation of a circle:
(x-h)^2+(y-k)^2=r^2
(h,k) - the coordinates of the center
r - the radius

The center is (4,0), the length of the radius is 2√3.
(x-4)^2+(y-0)^2=(2\sqrt{3})^2 \\&#10;\boxed{(x-4)^2+y^2=12}
8 0
3 years ago
Read 2 more answers
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