Sketch the two quadrilaterals and label them as shown in the figure below.
Let x = length of the 4th side of ABCD.
Because ABCD ~ EFGH, therefore
x/5 = 14/6
That is,
x = (5/6)*14 = 11.67 ft
Answer: D. 11.7 ft
f(x) = (x - 4)^2 - 1
g(x) = -(1/4) ( x - 4)^2 + 4
both the x and y values have to be the same. Start with the y values
f(x) = g(x)
(x - 4)^2 - 1 = -(1/4) (x - 4)^2 + 4 Add 1 to both sides.
(x - 4)^2 = -(1/4) (x - 4)^2 + 5 Add 1/4(x - 4)^2 to both sides.
(5/4) (x - 4)^2 = 5 Divide by 5/4 on both sides.
(x - 4)^2 = 5//(5/4)
(x - 4)^2 = (5/1)//5/4 Invert the second fraction and multiply
(x - 4)^2 = 5/1 * 4/5
(x - 4)^2 = 4 The 5s cancel
(x - 4)^2 = 4 Take the square root of both sides.
(x - 4) = +/- 2 Add 4 to each answer. Start with +2 on the right.
x - 4 + 4 = 2 + 4
x = 4 + 2 = 6
The x value that makes f(x)- g(x) = 0 is x = 6 The point is (6,3) answer.
Answer C.
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You do not need this next part. It is just for completeness.
x - 4 = - 2
x = 4 -2
x = 2
What are the y values for these 2 x values?
y = (x - 4)^2 - 1
y = (6 - 4)^2 - 1
y = 4 - 1
y = 3
The point where f(x) - g(x) = 0 is (6,3) <<<<<< Answer 1
The second point is
y = (x - 4)^2 - 1
y = (2 - 4)^2 - 1
y = (-2)^2 - 1
y = 4 - 1
y = 3
The second point is (2,3). Answer 2
Note the y values are the same. You might expect that.
Your answer would be 24, so you got it right.
This is because you need to find the lowest common multiple of 6 and 8, that is, the lowest number that divides by both 6 and 8.
We can do this by either writing out the multiples of 6 and 8 until you find a common one, or you can find the prime factors of 6 and 8 and multiply them:
6-> 3 × 2
8-> 2 × (4)->2 × 2
So we would need to do 3 × 2 × 2 × 2 = 3 × 8 = 24
I hope this helps!
Answer:
first one
Step-by-step explanation:
