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sertanlavr [38]
3 years ago
14

What will probably happen to a very dry forest

Chemistry
1 answer:
ElenaW [278]3 years ago
6 0

Answer:

Because of how dry the forest is there might be a fire a really big fire Explanation:

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Acetone is a three-carbon aldehyde. True/False.
stiv31 [10]

Answer: acetone is a ketone and not an aldehyde. Therefore it's false

Explanation:

Acetone is of structure CH3-CO-CH3

which makes it a ketone.

Both aldehyde and ketone have a carbonyl group but there is difference between aldehyde and ketone.

Aldehydes have a general formula R-CHO

where R is a methyl group including H atom, and CHO is the functional group.

While

Ketone have the general formula R-CO-Ri

where R and Ri are methyl groups excluding H atom, and CO is the functional group.

Hint: ketones usually end with the suffix "one" as in acetone.

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3 years ago
Which of the following is a consequence of humans using fossil fuels?
julia-pushkina [17]
I think it’s A, because all of these are related to fossil fuel somehow.
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3 years ago
if a scientist creates a new rock like substance in a laboratory, why wouldnt this type of material be classified as a true mine
ad-work [718]
The reason why it is not considered this is because the material was made in a lab, not through nature, which is what is required to be considered as a true mineral.
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What is not a guideline required for a valid evidence test?
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I just took that quiz , it’s A
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Will GIVE BRAINLIEST --A student makes a standard solution of potassium hydroxide by adding 14.555 g to 500.0 mL of water. Answe
leva [86]

Answer:

0.5188 M or 0.5188 mol/L

Explanation:

Concentration is calculated as <u>molarity</u>, which is the number of moles per litre.

***Molarity is represented by either "M" or "c" depending on your teacher. I will use "c".

The formula for molarity is:

c = \frac{n}{V}

n = moles (unit mol)

V = volume (unit L)

<u>Find the molar mass (M) of potassium hydroxide.</u>

M_{KOH} = \frac{39.098 g}{mol}+\frac{16.000 g}{mol}+\frac{1.008 g}{mol}

M_{KOH} = 56.106 \frac{g}{mol}

<u>Calculate the moles of potassium hydroxide.</u>

n_{KOH} = \frac{14.555 g}{1}*\frac{1mol}{56.106g}

n_{KOH} = 0.25941(9)mol

Carry one insignificant figure (shown in brackets).

<u>Convert the volume of water to litres.</u>

V = \frac{500.0mL}{1}*\frac{1L}{1000mL}

V = 0.5000L

Here, carrying an insignificant figure doesn't change the value.

<u>Calculate the concentration.</u>

c = \frac{n}{V}

c = \frac{0.25941(9)mol}{0.5000 L}              

c = 0.5188(3) \frac{mol}{L}         <= Keep an insignificant figure for rounding

c = 0.5188 \frac{mol}{L}              <= Rounded up

c = 0.5188M               <= You use the unit "M" instead of "mol/L"

The concentration of this standard solution is 0.5188 M.

7 0
3 years ago
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