Answer:
The answer is 30 g of sodium hydrocarbonate
Explanation:
This is a acid-base reaction, so in order to neutralise the spilled acid, the mol of spilled acid should be calculated.
M = n / V => n = M x V = 0.028 x 6.2 = 0.1736 mol
Since 1 mol of sulfuric acid generates 2 mol of H⁺, so the mole of H⁺ is 0.3472 mol or 0.35 mol with two significant figures.
To neutralized the acid, we need at least the same mole of base, so we need at least 0.35 mol of NaHCO₃, which can be converted to its mass at 29.4 g.
Since the answer need to be expressed in two significant figures and also need to make sure to neutralize all the acid, so we will use a little excess base. The answer is 30 g.
Answer:
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Explanation:
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Answer:
0.0225 M
Explanation:
In<em><u> one liter</u></em> of this solution, there are 45 mEq of Ca⁺².
1 mEq of Ca⁺² is equal to 20 mg of Ca⁺. We know this by dividing its molar mass (40) by the charge of the ion (2).
Meaning that <em>45 mEq of Ca⁺² is equal to (45 * 20) 900 mg of Ca⁺²</em>.
Now we <u>convert 900 mg of Ca⁺² into moles</u>, using its<em> molar mass</em>:
- 0.9 g Ca⁺² ÷ 40 g/mol = 0.0225 mol Ca⁺²
Finally we calculate the molarity of the solution:
- Molarity = moles / liters
- 0.0225 mol / 1 L = 0.0225 M
Answer:
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Explanation:
