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PIT_PIT [208]
3 years ago
15

What is the molarity of a solution that contains 45 mEq Ca“ per liter?

Chemistry
1 answer:
Mashutka [201]3 years ago
7 0

Answer:

0.0225 M

Explanation:

In<em><u> one liter</u></em> of this solution, there are 45 mEq of Ca⁺².

1 mEq of Ca⁺² is equal to 20 mg of Ca⁺. We know this by dividing its molar mass (40) by the charge of the ion (2).

Meaning that <em>45 mEq of Ca⁺² is equal to (45 * 20) 900 mg of Ca⁺²</em>.

Now we <u>convert 900 mg of Ca⁺² into moles</u>, using its<em> molar mass</em>:

  • 900 mg / 1000 = 0.9 g
  • 0.9 g Ca⁺² ÷ 40 g/mol = 0.0225 mol Ca⁺²

Finally we calculate the molarity of the solution:

  • Molarity = moles / liters
  • 0.0225 mol / 1 L = 0.0225 M
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